如何解决 Jupyter Notebook 中的内核错误？ (win64)答案

【问题标题】：How to solve kernel error in Jupyter notebook? (win64)如何解决 Jupyter Notebook 中的内核错误？ (win64)
【发布时间】：2020-05-15 17:44:17
【问题描述】：

我对 Jupyter 笔记本有点陌生。我在笔记本（Python 3）的右上角收到内核错误，我也无法运行任何代码。

这是错误：

    Traceback (most recent call last):
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\web.py", line 1699, in _execute
        result = await result
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
        yielded = self.gen.throw(*exc_info)  # type: ignore
      File "C:\Users\LAM\Anaconda3\lib\site-packages\notebook\services\sessions\handlers.py", line 72, in post
        type=mtype))
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
        value = future.result()
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
        yielded = self.gen.throw(*exc_info)  # type: ignore
      File "C:\Users\LAM\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 88, in create_session
        kernel_id = yield self.start_kernel_for_session(session_id, path, name, type, kernel_name)
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
        value = future.result()
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
        yielded = self.gen.throw(*exc_info)  # type: ignore
      File "C:\Users\LAM\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 101, in start_kernel_for_session
        self.kernel_manager.start_kernel(path=kernel_path, kernel_name=kernel_name)
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
        value = future.result()
      File "C:\Users\LAM\Anaconda3\lib\site-packages\tornado\gen.py", line 209, in wrapper
        yielded = next(result)
      File "C:\Users\LAM\Anaconda3\lib\site-packages\notebook\services\kernels\kernelmanager.py", line 168, in start_kernel
        super(MappingKernelManager, self).start_kernel(**kwargs)
      File "C:\Users\LAM\Anaconda3\lib\site-packages\jupyter_client\multikernelmanager.py", line 110, in start_kernel
        km.start_kernel(**kwargs)
      File "C:\Users\LAM\Anaconda3\lib\site-packages\jupyter_client\manager.py", line 240, in start_kernel
        self.write_connection_file()
      File "C:\Users\LAM\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 547, in write_connection_file
        kernel_name=self.kernel_name
      File "C:\Users\LAM\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 212, in write_connection_file
        with secure_write(fname) as f:
      File "C:\Users\LAM\Anaconda3\lib\contextlib.py", line 112, in __enter__
        return next(self.gen)
      File "C:\Users\LAM\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 102, in secure_write
        with os.fdopen(os.open(fname, open_flag, 0o600), mode) as f:
    PermissionError: [Errno 13] Permission denied: 'C:\\Users\\LAM\\AppData\\Roaming\\jupyter\\runtime\\kernel-a1df27b5-fc61-47a3-9f67-f3a880aeb05c.json'

【问题讨论】：

看起来你遇到了这个问题：github.com/jupyter/jupyter_client/issues/479。如果是这样，解决方法是升级jupyter_core 包。假设它与 conda 一起安装，您可以通过打开 Anaconda 命令提示符并运行 conda update jupyter_core 来做到这一点。
请向您的供应商寻求有关您产品的帮助。这个论坛是关于编程的，你已经标记为C 一个与该语言无关的问题。
如果我卸载anaconda并尝试重新安装，它会解决问题吗？

标签： python django python-3.x jupyter-notebook

【解决方案1】：

请尝试创建一个新的 conda 环境。使用命令创建 conda 环境：

conda create -n <env_name> -c intel python=3.6

使用命令激活环境：

source activate <env_name>

请在此环境中安装所需的软件包。请使用以下命令安装 ipykernal：

conda install ipykernel
ipython kernel install --name <env_name> --user

从你的 jupyter notebook 中选择已安装的 ipykernal。希望这会有所帮助。

请参考以下链接，https://github.com/jupyter/notebook/issues/2301

【讨论】：