【发布时间】:2015-12-05 09:19:45
【问题描述】:
我正在尝试混合两个图像,如 here 所示。
这是我的全部代码
#include <cv.h>
#include <highgui.h>
#include <iostream>
using namespace cv;
int main( int argc, char** argv )
{
double beta; double input;
Mat src1, src2, dst;
/// Ask the user enter alpha
std::cout<<" Simple Linear Blender "<<std::endl;
std::cout<<"-----------------------"<<std::endl;
src1 = imread("face.jpg");
src2 = imread("necklace1.png");
if( !src1.data ) { printf("Error loading src1 \n"); return -1; }
if( !src2.data ) { printf("Error loading src2 \n"); return -1; }
double alpha = 0.1; // something
int min_x = ( (src1.cols - src2.cols)/2 );
int min_y = ( (src1.rows - src2.rows)/2 );
int width, height;
// min_x, min_y should be valid in src1 and [width height] = size(src2)
cv::Rect roi = cv::Rect(min_x, min_y, src2.cols, src2.rows);
// "out_image" is the output ; i.e. src1 with a part of it blended with src2
cv::Mat out_image = src1.clone();
// Set the ROIs for the selected sections of src1 and out_image (the same at the moment)
cv::Mat src1_roi= src1(roi);
cv::Mat out_image_roi = out_image(roi);
// Blend the ROI of src1 with src2 into the ROI of out_image
cv::addWeighted(src1_roi,alpha,src2,1-alpha,0.0,out_image_roi);
imshow( "Linear Blend", out_image );
waitKey(0);
return 0;
}
但是得到的输出是
我希望这条项链像以前一样透明。怎么做?
我试过cvtColor( out_image_roi,out_image_roi, CV_BGR2BGRA );之前cv::addWeighted(src1_roi,alpha,src2,1-alpha,0.0,out_image_roi);
然后输出只是人脸图像。
【问题讨论】:
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输入图像是3通道图像吗?也许您只需要在混合之前将其转换为具有 4 个通道。 (例如克隆后):cv::Mat convert_out_img = cv::Mat(out_img,rows,cols,CV_8UC4);
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@Gombat 如果我们做 cv::Mat convert_out_img = cv::Mat(out_img,rows,cols,CV_8UC4); convert_out_img 将是新的空白图像吗?
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对不起,你应该这样做:cv::Mat conv_img = cv::Mat(img.rows,img.cols,CV_8UC4)。此图像为空白。接下来定义如何填充它。 int from_to[] = {0,0,1,1,2,2,3,3};并填写:cv::mixChannels(&img,2,&conv_img,1,from_to,4);
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@Gombat 它不工作。请尝试将您的逻辑插入我的代码并尝试.. 我认为现在转换后的图像和 src1 有指向不同地址的指针。所以混合是行不通的
标签: c++ opencv image-processing alpha alphablending