【发布时间】:2019-10-13 10:14:58
【问题描述】:
我有一个实现这样的自动编码器的 keras 代码:
ENCODING_DIM = 5
# input placeholder
input_img = tf.keras.layers.Input(shape=(320,))
# this is the encoded representation of the input
encoded = tf.keras.layers.Dense(35, activation='relu')(input_img)
encoded = tf.keras.layers.Dense(20, activation='relu')(encoded)
encoded = tf.keras.layers.Dense(ENCODING_DIM, activation='relu')(encoded)
decoded = tf.keras.layers.Dense(20, activation='relu')(encoded)
decoded = tf.keras.layers.Dense(35, activation='relu')(decoded)
decoded = tf.keras.layers.Dense(320, activation='sigmoid')(decoded)
autoencoder = tf.keras.models.Model(input_img, decoded)
encoder = tf.keras.models.Model(input_img, encoded)
encoded_input = tf.keras.layers.Input(shape=(ENCODING_DIM,))
decoder_layer = autoencoder.layers[-1]
#decoded_input = tf.keras.models.Model(encoded_input,decoder_layer(encoded_input))
autoencoder.compile(optimizer='nadam', loss='binary_crossentropy')
from keras.callbacks import ModelCheckpoint
效果很好。
现在我想要可变的输入尺寸(例如,第一个向量 [320x1]、第二个 [280x1] 等...)
现在我尝试这样做:
ENCODING_DIM = 5
# input placeholder
input_img = tf.keras.layers.Input(shape=(None,))
# this is the encoded representation of the input
encoded = tf.keras.layers.Dense(35, activation='relu')(input_img)
encoded = tf.keras.layers.Dense(20, activation='relu')(encoded)
encoded = tf.keras.layers.Dense(ENCODING_DIM, activation='relu')(encoded)
decoded = tf.keras.layers.Dense(20, activation='relu')(encoded)
decoded = tf.keras.layers.Dense(35, activation='relu')(decoded)
decoded = tf.keras.layers.Dense(320, activation='sigmoid')(decoded)
autoencoder = tf.keras.models.Model(input_img, decoded)
encoder = tf.keras.models.Model(input_img, encoded)
encoded_input = tf.keras.layers.Input(shape=(ENCODING_DIM,))
decoder_layer = autoencoder.layers[-1]
#decoded_input = tf.keras.models.Model(encoded_input,decoder_layer(encoded_input))
autoencoder.compile(optimizer='nadam', loss='binary_crossentropy')
from keras.callbacks import ModelCheckpoint
但它返回如下错误:
ValueError Traceback (most recent call last)
<ipython-input-24-7764c4707491> in <module>()
14
15 # this is the encoded representation of the input
---> 16 encoded = tf.keras.layers.Dense(35, activation='relu')(input_img)
17 encoded = tf.keras.layers.Dense(20, activation='relu')(encoded)
18 encoded = tf.keras.layers.Dense(ENCODING_DIM, activation='relu')(encoded)
2 frames
/usr/local/lib/python3.6/dist-packages/tensorflow/python/keras/layers/core.py in build(self, input_shape)
935 input_shape = tensor_shape.TensorShape(input_shape)
936 if tensor_shape.dimension_value(input_shape[-1]) is None:
--> 937 raise ValueError('The last dimension of the inputs to `Dense` '
938 'should be defined. Found `None`.')
939 last_dim = tensor_shape.dimension_value(input_shape[-1])
ValueError: The last dimension of the inputs to `Dense` should be defined. Found `None`.
如何实现具有不同输入维度的自动编码器?
【问题讨论】:
-
在您的情况下,密集层将创建 35 个神经元,每个神经元将连接到每个输入特征(共 320 个)。例如,它将初始化大小为 35x320 的权重矩阵。当输入大小未知时,至少在涉及密集层时,无法初始化这样的矩阵。您必须将输入填充到某个最大可能的输入长度(320?)以应用您定义的模型。
-
谢谢。 pad 解决方案似乎是解决可变输入尺寸的唯一方法
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@y.selivonchyk 我支持您的回答并建议将其从评论移至回答
标签: python tensorflow keras autoencoder