从 wrk 输出中提取文本答案

【问题标题】：Extract text from wrk output从 wrk 输出中提取文本
【发布时间】：2019-08-26 08:27:09
【问题描述】：

我正在使用 wrk2 作为 Jenkins 上的工作运行负载测试。我想将负载测试的结果发送到 Graylog，但我只想存储 Requests/Sec 和平均延迟。

这是输出的样子：

Running 30s test @ https://example.com

1 threads and 100 connections
  Thread calibration: mean lat.: 8338.285ms, rate sampling interval: 19202ms
  Thread Stats   Avg      Stdev     Max   +/- Stdev
    Latency    16.20s     6.17s   29.64s    65.74%
    Req/Sec     5.00      0.00     5.00    100.00%
  Latency Distribution (HdrHistogram - Recorded Latency)
 50.000%   15.72s 
 75.000%   20.81s 
 90.000%   24.58s 
 99.000%   29.13s 
 99.900%   29.66s 
 99.990%   29.66s 
 99.999%   29.66s 
100.000%   29.66s 

  Detailed Percentile spectrum:
       Value   Percentile   TotalCount 1/(1-Percentile)

    4497.407     0.000000            1         1.00
    7561.215     0.100000           11         1.11
   11100.159     0.200000           22         1.25
   12582.911     0.300000           33         1.43
   14565.375     0.400000           44         1.67
   15720.447     0.500000           54         2.00
   16416.767     0.550000           60         2.22
   17301.503     0.600000           65         2.50
   18464.767     0.650000           71         2.86
   19185.663     0.700000           76         3.33
   20807.679     0.750000           81         4.00
   21479.423     0.775000           84         4.44
   22347.775     0.800000           87         5.00
   22527.999     0.825000           90         5.71
   23216.127     0.850000           93         6.67
   23478.271     0.875000           95         8.00
   23805.951     0.887500           96         8.89
   24723.455     0.900000           98        10.00
   25067.519     0.912500           99        11.43
   25395.199     0.925000          101        13.33
   26525.695     0.937500          102        16.00
   26525.695     0.943750          102        17.78
   26705.919     0.950000          103        20.00
   28065.791     0.956250          104        22.86
   28065.791     0.962500          104        26.67
   28377.087     0.968750          105        32.00
   28377.087     0.971875          105        35.56
   28475.391     0.975000          106        40.00
   28475.391     0.978125          106        45.71
   28475.391     0.981250          106        53.33
   29130.751     0.984375          107        64.00
   29130.751     0.985938          107        71.11
   29130.751     0.987500          107        80.00
   29130.751     0.989062          107        91.43
   29130.751     0.990625          107       106.67
   29655.039     0.992188          108       128.00
   29655.039     1.000000          108          inf
#[Mean    =    16199.756, StdDeviation   =     6170.105]
#[Max     =    29638.656, Total count    =          108]
#[Buckets =           27, SubBuckets     =         2048]
----------------------------------------------------------
  130 requests in 30.02s, 13.44MB read
  Socket errors: connect 0, read 0, write 0, timeout 1192
Requests/sec:      4.33
Transfer/sec:    458.47KB

有谁知道我可以如何提取每秒请求数（在底部）和平均延迟以作为 JSON 参数发送？

预期输出为："latency": 16.2, "requests_per_second": 4.33

【问题讨论】：

标签： jenkins awk sed graylog2 wrk

【解决方案1】：

您没有提供预期的输出，所以您的问题不清楚，但这是您想要的吗？

$ awk 'BEGIN{a["Latency"]; a["Requests/sec:"]} ($1 in a) && ($2 ~ /[0-9]/){print $1, $2}' file
Latency 16.20s
Requests/sec: 4.33

根据您向问题添加预期输出而更新：

$ awk '
    BEGIN { map["Latency"]="latency"; map["Requests/sec:"]="requests_per_second" }
    ($1 in map) && ($2 ~ /[0-9]/) { printf "%s\"%s\": %s", ofs, map[$1], $2+0; ofs=", " }
    END { print "" }
' file
"latency": 16.2, "requests_per_second": 4.33

【讨论】：

感谢您的回答，并为没有通过预期的输出使问题更清晰而道歉 - 我现在已经添加了。如果我将它与 jq 结合起来，这看起来仍然可以工作。
我根据您提供的新预期输出更新了我的答案。