BeautifulSoup 从课堂中获得价值

Question

我在使用 BeautifulSoup 时遇到了问题。 这是我想做的：

对于我阅读的每个html页面中的每个表单，我都想获取“action”指向的URL。

这是我的代码：

def myfunction(path)
    from bs4 import BeautifulSoup

    #Retrieve htmlFiles from a folder
    pages = find_files(path, '.html') #as a list
    for page in pages:
        stream = open(page, "rw")
        soup = BeautifulSoup(stream, "lxml")
        formsoup = soup.find('form', attrs={"method":u"post"})
        if formsoup is not None:
           action = soup.find('form', attrs={"method":u"post"}).findAll("action") 
           print "Action is => %s\n" % action
           print ("Source: %s\ncode: %s\n\n\n\n\n" % (page, formsoup))
    stream.close()

这是我得到的结果：

Action is => []

    Source: mysource.html
    code: <form accept-charset="UTF-8" action="http://actionIshouldget.com/" id="user-login" method="post"><div><div class="form-item form-type-textfield form-item-name">
[... hidhing about ~20 lines that are useless for me]

这是我应该得到的结果：

Action is => http://actionIshouldget.com/

    Source: mysource.html
    code: <form accept-charset="UTF-8" action="http://actionIshouldget.com/" id="user-login" method="post"><div><div class="form-item form-type-textfield form-item-name">
[... hidhing about ~20 lines that are useless for me]

我没有设法使用for form in soup.find('form', attrs={"method":u"post"}) 或正则表达式...

Answer 1

findAll() 将尝试在您拥有的结构中查找子元素，并在您的情况下搜索<action> 元素。

你试过了吗？

formsoup = soup.find('form', attrs={"method":u"post"})
formsoup['action']