使用 beautifulsoup Python 检查 HTML 中是否存在特定类

Question

我正在编写一个脚本，并想检查一个特定的类是否存在于 html 中。

from bs4 import BeautifulSoup
import requests

def makesoup(u):
    page=requests.get(u)
    html=BeautifulSoup(page.content,"lxml")
    return html
html=makesoup('https://www.yelp.com/biz/soco-urban-lofts-dallas')

print("3 star",html.has_attr("i-stars i-stars--large-3 rating-very-large")) #it's returning False
res = html.find('i-stars i-stars--large-3 rating-very-large")) #it's returning NONE

请指导我如何解决此问题？如果我以某种方式获得标题（标题 =“3.0 星级”），这也对我有用。控制台 HTML 截图

<div class="i-stars i-stars--large-3 rating-very-large" title="3.0 star rating">
  <img class="offscreen" height="303" src="https://s3-media1.fl.yelpcdn.com/assets/srv0/yelp_design_web/8a6fc2d74183/assets/img/stars/stars.png" width="84" alt="3.0 star rating">
    </div>

Answer 1

has_attr 是一种检查元素是否具有您想要的 属性 的方法。 class 是一个属性，i-stars i-stars--large-3 rating-very-large 是它的值。

find 需要 CSS selectors，而不是类值。所以你应该改用html.find('div.i-stars.i-stars--large-3.rating-very-large')。这是因为您正在寻找具有所有这些类的div。

Answer 2

在获取确切的课程时遇到了类似的问题。它们可以作为字典对象返回，如下所示。

html = '<div class="i-stars i-stars--large-3 rating-very-large" title="3.0 star rating">'
soup = BeautifulSoup(html, 'html.parser')
find = soup.div
classes = find.attrs['class']
c1 = find.attrs['class'][0]
print (classes, c1)

Answer 3

from bs4 import BeautifulSoup
import requests

def makesoup(u):
    page=requests.get(u)
    html=BeautifulSoup(page.content,"lxml")
    return html
html=makesoup('https://www.yelp.com/biz/soco-urban-lofts-dallas')
res = html.find(class_='i-stars i-stars--large-3 rating-very-large')
if res:
    print("3 star", 'whatever you want print')

出来：

3 star whatever you want print