需要帮助确定文本文件中文本的一般格式答案

【问题标题】：need help determining the general formatting of text in a text file需要帮助确定文本文件中文本的一般格式
【发布时间】：2020-02-15 00:33:24
【问题描述】：

如果有人有经验，这个问题与 HECRAS 有关，但一般来说，这只是一个关于将文本文件写入非常特殊的格式以供 HECRAS 软件读取的问题。

基本上我正在读取一些文件并更改一些数字，然后将其写回，但我似乎无法完美匹配初始格式。

这是原始文件的样子：

Type RM Length L Ch R = 1 ,229.41  ,21276,21276,21276
Node Last Edited Time=Oct-17-2019 15:52:28
#Sta/Elev= 452 
       0  20.097  67.042   9.137   67.43   9.139  68.208   9.073  68.598   9.129
  68.986   9.086  70.538   9.071  70.926   9.042  71.984   9.046   72.48   9.025
  73.646   9.056  74.368   9.034  75.586   9.042   76.55   9.017  77.138   9.047
  78.304   8.989   79.47   9.025   80.19   9.001   81.41   9.003  81.974   8.978
   83.83   9.005  85.284   9.079  85.682   9.068   86.97   9.118  88.012   9.223
   88.79   9.239   89.65   9.316  90.342   9.324  91.134   9.475  91.966   9.525
  92.282   9.589  93.346   9.546  94.222   9.557  94.922   9.594   95.71   9.591
  96.546    9.64  97.286   9.574   98.87   9.688  99.258   9.673  99.642   9.712
#Mann= 3 , 0 , 0 
       0     .09       0   246.4    .028       0   286.4     .09       0
Bank Sta=246.4,286.4
XS Rating Curve= 0 ,0
XS HTab Starting El and Incr=1.708,0.1, 500 
XS HTab Horizontal Distribution= 5 , 5 , 5 
Exp/Cntr=0.3,0.1

我对 Sta/Elev 数据感兴趣...它看起来像是一些右对齐的制表符/空格？站/高程对中的分隔格式，每行 5 个。也许每对 16 个字符？？

我尝试了很多不同的东西，我当前的代码是：

with open('C:/Users/deden/Desktop/t/test.g01','w') as out:
    out.write(txt[:idx[0][0]])
    out.write(txt[idx[0][0]:idx[0][0]+bounds[0]])
    out.write('#'+raw_SE.split('\n')[0]+'\n')
    i = 0 
    while i <= len(new_SE):
        out.write('\t'.join(new_SE[i:i+10])+'\n')
        i+=10
    out.write(txt[idx[0][0]+bounds[1]:idx[1][0]])

这是一个有点hacky atm，仍在尝试解决，重要的部分只是：

while i <= len(new_SE):
    out.write('\t'.join(new_SE[i:i+10])+'\n')
    i+=10

new_SE 只是一个站点/海拔列表：

['0', '30.097', '67.042', '19.137', '67.43', '19.139', '68.208', '19.073', '68.598', '19.128999999999998' ...]

我也尝试过使用以下方法来玩弄正当的一面：

'%8s  %8s' % (tmp[0], tmp[1])

文本之间基本上有 8 个空格，但要右对齐

老实说苦苦挣扎...如果有人可以在 #Sta/Elev= 452 和 #Mann 之间重新创建原始文本，我将永远感激不尽，如果有人想试一试，这里是完整列表：

new_SE = ['0', '30.097', '67.042', '19.137', '67.43', '19.139', '68.208', '19.073', '68.598', '19.128999999999998', '68.986', '19.086', '70.538', '19.070999999999998', '70.926', '19.042', '71.984', '19.046', '72.48', '19.025', '73.646', '19.055999999999997', '74.368', '19.034', '75.586', '19.042', '76.55', '19.017', '77.138', '19.047', '78.304', '18.989', '79.47', '19.025', '80.19', '19.000999999999998', '81.41', '19.003', '81.974', '18.978', '83.83', '19.005000000000003', '85.284', '19.079', '85.682', '19.067999999999998', '86.97', '19.118000000000002', '88.012', '19.223', '88.79', '19.239', '89.65', '19.316000000000003', '90.342', '19.323999999999998', '91.134', '19.475', '91.966', '19.525', '92.282', '19.589', '93.346', '19.546', '94.222', '19.557000000000002', '94.922', '19.594', '95.71', '19.591', '96.546', '19.64', '97.286', '19.573999999999998', '98.87', '19.688000000000002', '99.258', '19.673000000000002', '99.642', '19.712']

【问题讨论】：

标签： python string format

【解决方案1】：

不太确定我是否理解正确 - 请考虑查看

# with open('C:/Users/deden/Desktop/t/test.g01','w') as out:
    for i in range(0, len(new_SE), 10):
        row = [f'{float(v):8.3f}' for v in new_SE[i:i+10]]
        out.write(''.join(r) + '\n')

#    0.000  30.097  67.042  19.137  67.430  19.139  68.208  19.073  68.598  19.129
#   68.986  19.086  70.538  19.071  70.926  19.042  71.984  19.046  72.480  19.025
#   73.646  19.056  74.368  19.034  75.586  19.042  76.550  19.017  77.138  19.047
#   78.304  18.989  79.470  19.025  80.190  19.001  81.410  19.003  81.974  18.978
#   83.830  19.005  85.284  19.079  85.682  19.068  86.970  19.118  88.012  19.223
#   88.790  19.239  89.650  19.316  90.342  19.324  91.134  19.475  91.966  19.525
#   92.282  19.589  93.346  19.546  94.222  19.557  94.922  19.594  95.710  19.591
#   96.546  19.640  97.286  19.574  98.870  19.688  99.258  19.673  99.642  19.712

【讨论】：