【发布时间】:2023-11-20 20:48:01
【问题描述】:
1-我已经准备好将 de xml 文件转换为 csv 的代码。但实际上我需要多次执行此操作,然后每次都需要更改程序中 xml 文件的名称。我想做一个循环来读取文件夹位置中的每个“.xml”文件并执行所有文件。有我原来的代码
import xml.etree.ElementTree as ET
import csv
tree = ET.parse("Shot_30AA.xml")
root = tree.getroot()
Shot_30AA = open('Shot_30AA.csv', 'w', newline='')
csvwriter = csv.writer(Shot_30AA)
head = []
ShotCode = root.attrib['ShotCode']
csvwriter.writerow(['ShotCode', ShotCode])
head.append(ShotCode)
for member in root.getchildren():
submembers = member.getchildren()
keys = submembers[0].attrib.keys()
csvwriter.writerow ("\n")
csvwriter.writerow(keys)
for submember in submembers:
row_data = [submember.attrib[k] for k in keys]
csvwriter.writerow(row_data )
Shot_30AA.close()
我尝试在我的文件夹中执行此操作,添加闲置代码只执行一次
path = 'C:/Users/Desktop/Program'
for filename in os.listdir(path):
if not filename.endswith('.xml'): continue
ShotFile = os.path.join(path, filename)
tree = ET.parse(ShotFile)
root = tree.getroot()
filename = open( filename'.csv', 'w', newline='')
csvwriter = csv.writer(filename)
head = []
ShotFile = open('ShotFile.csv', 'w', newline='')
csvwriter = csv.writer(Shot_30AA)
head = []
ShotCode = root.attrib['ShotCode']
csvwriter.writerow(['ShotCode', ShotCode])
head.append(ShotCode)
for member in root.getchildren():
submembers = member.getchildren()
keys = submembers[0].attrib.keys()
csvwriter.writerow ("\n")
csvwriter.writerow(keys)
for submember in submembers:
row_data = [submember.attrib[k] for k in keys]
csvwriter.writerow(row_data )
ShotFile.close()
我希望通过一次运行获得所有 csv 格式的文件。
【问题讨论】:
标签: python xml csv for-loop rename