RegEx 将文本字符串拆分为 dict 作为组答案

【问题标题】：RegEx split text string into dict as groupRegEx 将文本字符串拆分为 dict 作为组
【发布时间】：2016-02-19 22:58:06
【问题描述】：

我正在尝试将 RegEx 字符串输出并作为文本组添加到字典中，为此我使用 re.split()。

我的字符串输出是：

mpathag (36005076801b2014804000000000001cd) dm-7 Test ,2145
size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw
|-+- policy='service-time 0' prio=50 status=active
| |- 12:0:1:3 sdas  66:192 active ready  running
| `- 13:0:1:3 sdbi  67:192 active ready  running
`-+- policy='service-time 0' prio=10 status=enabled
  |- 12:0:0:3 sdak  66:64  active ready  running
  `- 13:0:0:3 sdba  67:64  active ready  running
mpathz (36005076801b2014804000000000001c4) dm-0 Test ,2145
size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw
|-+- policy='service-time 0' prio=50 status=active
| |- 12:0:0:0 sdah  66:16  active ready  running
| `- 13:0:0:0 sdax  67:16  active ready  running
 `-+- policy='service-time 0' prio=10 status=enabled
   |- 10:0:0:0 sdb   8:16   active ready  running
   `- 13:0:1:0 sdbf  67:144 active ready  running

这里是我的解析代码：

    output = "mpathag (36005076801b2014804000000000001cd) dm-7 Test ,2145\
    size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw\
    |-+- policy='service-time 0' prio=50 status=active\
    | |- 12:0:1:3 sdas  66:192 active ready  running\
    | `- 13:0:1:3 sdbi  67:192 active ready  running\
    `-+- policy='service-time 0' prio=10 status=enabled\
      |- 12:0:0:3 sdak  66:64  active ready  running\
      `- 13:0:0:3 sdba  67:64  active ready  running\
    mpathz (36005076801b2014804000000000001c4) dm-0 Test ,2145\
    size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw\
    |-+- policy='service-time 0' prio=50 status=active\
    | |- 12:0:0:0 sdah  66:16  active ready  running\
    | `- 13:0:0:0 sdax  67:16  active ready  running\
     `-+- policy='service-time 0' prio=10 status=enabled\
       |- 10:0:0:0 sdb   8:16   active ready  running\
       `- 13:0:1:0 sdbf  67:144 active ready  running"

    devices = re.split('mpath', output)
    for dev in devices:
       print dev

我的问题是 re.split 从文本中删除了模式，可以在不删除分隔符的情况下拆分？

输出结果是这样的：

ag (36005076801b2014804000000000001cd) dm-7 Test ,2145    
size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw    
|-+- policy='service-time 0' prio=50 status=active    
| |- 12:0:1:3 sdas  66:192 active ready  running    
| `- 13:0:1:3 sdbi  67:192 active ready  running    
`-+- policy='service-time 0' prio=10 status=enabled      
  |- 12:0:0:3 sdak  66:64  active ready  running      
  `- 13:0:0:3 sdba  67:64  active ready  running

【问题讨论】：

当您的字符串没有任何新行时，如何获得格式良好的输出？

标签： python regex string-split

【解决方案1】：

如果模式包含捕获组，则不会排除该组：

>>> re.split(',', '1,2,3')  # without capturing group
['1', '2', '3']
>>> re.split('(,)', '1,2,3')  # with capturing group
['1', ',', '2', ',', '3']
>>> xs = re.split('(,)', '1,2,3')
>>> [part1+part2 for part1, part2 in zip(xs[1::2], xs[2::2])]
[',2', ',3']

devices = re.split('(mpath)', output)
for part1, part2 in zip(devices[1::2], devices[2::2]):
    print part1 + part2

【讨论】：