如何进行循环以从列表中获取特定项目？ - Python

Question

关于节目：

在这个程序中，我需要先获取用户的输入以进行“测验” 问号。的问题，然后问问题文本和 4 'answers' ，并从这 4 个答案中要求正确答案。 重复没有。问题。

就像一个“测验制作者”

list_of_questions 存储问题的文本

list_of_keys 存储所有问题的输入“答案”（按顺序） 示例：

list_of_keys = [Q1_Answer1, Q1_Answer2, Q1_Answer3, Q1_Answer4, Q2_Answer1, Q2_Answer2, Q2_Answer3, Q2_Answer4, Q3_Answer1 etc...]

在 start_quiz() 中，我需要先打印第一个问题文本和 4 个答案，然后打印第二个问题文本和 4 个答案等...

使用循环从列表中获取特定项目

但是我在下面制作的循环：只是再次打印相同的前 4 个答案。

我找不到从列表中正确获取项目的解决方案。

我试过了，但没用：（超出范围错误）

var1 = 0
for I in main_list:
    answer_amount = 4
    if answer_amount > 0:
        var1 += 1
        print(list_of_keys[var1])

整个代码：

from questionclass import Question_template

main_list = []

list_of_questions = []
list_of_answers = []
list_of_keys = []


print("\n Quiz maker \n")


def make_quiz():
    X = 0
    Z = 0
    Y = 0
    amount_of_answers = 4
    question_amount = int(input(" Enter number of questions for     your quiz: "))
    while question_amount > 0:
        question_amount -= 1
        X += 1
        list_of_questions.append(str(input(" Text for question no." + str(X) + ": ")))
        while amount_of_answers > 0:
            amount_of_answers -= 1
            Y += 1
            list_of_keys.append((str(Y) + ".") + str(input("  Answer no." + str(Y) + ": ")))
        amount_of_answers = 4
        list_of_answers.append(int(input("\nwhich answer is the correct answer?\n")))
        Y = 0
    for question in list_of_questions:
        main_list.append(Question_template(question, list_of_keys[Z], list_of_answers[Z]))
        Z += 1
    start_quiz()

def start_quiz():
    key = int(input("\n enter 0 to start quiz: "))
    score = 0
    If key == 0:
        for question in main_list: 
            print(question.promt) # printing the question text
            amount_of_answers = 4


            for i in list_of_keys:     ####THIS LOOP HERE#### 
                if amount_of_answers > 0:
                    print(i)
                    amount_of_answers -= 1


            answer = int(input(""))
            if answer == list_of_answers[0]:
                score += 1

makequiz()

问题类别：

class Question_template:
    def __init__(self, promt, answers, correct):
        self.promt = promt
        self.answers = answers
        self.correct = correct

Answer 1

由于您每次都从 list_of_keys 的起点进行迭代，因此您每次都会得到相同的答案。对于问题 1，您在 0 到 4 之间迭代，对于问题 2，您再次在 0 4 之间迭代。但是，对于问题 2，您的信息介于 4 到 8 之间。因此，您应该添加一个密钥计数器来存储您要查找的问题。因此，我添加了 keyCounter，并为每个问题将其增加到 4。除此之外，您还应该从 list_of_keys 中的那个点开始，例如 list_of_keys[keyCounter:]。

def start_quiz():
    key = int(input("\n enter 0 to start quiz: "))
    score = 0
    keyCounter = 0
    if key == 0:
        for question in main_list:
            print(question.promt) # printing the question text
            amount_of_answers = 4

            for i in list_of_keys[keyCounter:]:     ####THIS LOOP HERE####
                if amount_of_answers > 0:
                    print(i)
                    amount_of_answers -= 1
            keyCounter = keyCounter + 4