Python 在工作正则表达式上不返回匹配项

Question

我在 python 中有一个字符串（不是原始的），类似于以下内容：

Plenary Papers (1)
Peer-reviewed Papers (113)
PLENARY MANUSCRIPTS (1)
First Author Index

Harrer
Plenary Papers

One Some title
John W. Doe
2018 Physics SOmething Proceedings
Full Text: Download PDF - PER-Central Record
Show Abstract - Show Citation
PEER REVIEWED MANUSCRIPTS (113)
First Author Index

Doe · Doe2 · Doe3 · Jonathan
Peer-reviewed Papers

Two some title
Alex White, Paul Klee, and Jacson Pollock
2018 Physics Research Conference Proceedings, doi:10.1234/perc.2018.pr.White
Full Text: Download PDF - PER-Central Record
Show Abstract - Show Citation

Tree Some title
Suzanne Heck, Alex Someone, John I. Smith, and Andrew Bourgogne
2018 Physics Education Research Conference Proceedings, doi:10.2345/perc.2018.pr.Heck
Full Text: Download PDF - PER-Central Record
Show Abstract - Show Citation

..

我想抓取这三篇论文的元数据，即每个标题后面的那几行（例如“One Some title”、“John W. Doe”和 2018 Physics Something Proceedings”）。

我想在选择的开始和结束时使用两种模式：

'r"\n\n"' 和 'r"Show Abstract - Show Citation"'。

这（几乎）适用于https://regex101.com/使用这个正则表达式：

\n\n(.*?)Show Abstract - Show Citation

一个小问题是它对前两篇论文很贪心。

但不是在 python 中：

    pattern=r"\n\n(.*?)Show Abstract - Show Citation"

    re.findall(pattern, titles) #titles is the text above

    #output is []
    pattern_only_one_line=r"\nShow Abstract - Show Citation"

    re.findall(pattern_only_one_line, titles)

    #output shows three lines

这可能是原始字符串的另一个问题吗？

Answer 1

re.DOTALL 标志丢失。没有它 . 将无法匹配换行符。

但我们可以做得更好（当然取决于您的具体需求）：https://regex101.com/r/iN6pX6/199

import re
import pprint

titles = '''
[Omitted for brevity]
..
'''

pattern = r'''
(?P<title>[^\n]+)\n
(?P<subtitle>[^\n]+)\n
((?P<etc>[^\n].*?)\n\n|\n)
'''

# Make sure we don't have any extraneous whitespace but add the separator
titles = titles.strip() + '\n\n'

for match in re.finditer(pattern, titles, re.DOTALL | re.VERBOSE):
    title = match.group('title')
    subtitle = match.group('subtitle')
    etc = match.group('etc')
    print('## %r' % title)
    print('# %r' % subtitle)
    if etc:
      print(etc)
    print()
    # pprint.pprint(match.groupdict())