【发布时间】:2015-08-08 02:46:53
【问题描述】:
我是 Flask 和 Javascript 的新手。我正在尝试上传文件并将其列之一用作下拉菜单中的选项。请纠正我的错误。
代码如下:
烧瓶:
from flask import Flask, render_template, redirect, url_for, request, flash, send_from_directory
from werkzeug import secure_filename
import os
import pandas as pd
import numpy as np
import json
UPLOAD_FOLDER = 'uploads/'
ALLOWED_EXTENSIONS = set(['csv'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
return '.' in filename and filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
if request.method == 'POST':
file = request.files['data_file']
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
data = pd.read_csv(os.path.join(app.config['UPLOAD_FOLDER'], filename))
names = data['some_column']
return redirect(url_for('drop_down', names=names))
#return render_template('drop_down.html', names=names)
return render_template('file_upload.html')
@app.route('/meta')
def drop_down():
return render_template('drop_down.html')
Javascript:
function my_script(){
console.log('script called.');
//var cars = ["Volvo","Ferrari","Audi","BMW","Mercedes","Porche","Saab","Avanti"];
var cars = {{ names|safe }};
console.log('cars assigned.');
function make_drop_down(list_of_names, element_id){
select_elem = document.getElementById(element_id)
if(select_elem){
for(var i = 0; i < list_of_names.length; i++) {
var option = document.createElement('option');
option.innerHTML = list_of_names[i];
option.value = list_of_names[i];
select_elem.appendChild(option);
}
}
};
console.log("Making Drop Downs!!");
make_drop_down(cars, 'drop_down_1');
make_drop_down(cars, 'drop_down_2');
console.log("Made Drop Downs!!");
};
html:
<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" src="static/drop_down.js"></script>
<title>DROP DOWN</title>
</head>
<body onload="my_script()">
<select id="drop_down_1">
<option>Choose Option 1</option>
</select>
</br></br>
<select id="drop_down_2">
<option>Choose Option 2</option>
</select>
</body>
</html>
我在控制台上收到以下错误: ReferenceError: my_script 未定义
【问题讨论】:
-
您如何将 {{ names|safe }} 中的名称传递给您的 javascript?
标签: javascript python arrays flask