【发布时间】:2015-05-11 05:43:19
【问题描述】:
我目前有一个通过 POST 接收文件内容的 Flask 路由, 并将其存储在文件系统上,例如:
@app.route('/upload', methods=['POST'])
def upload_file():
def allowed_file(f):
return True
file = request.files['file']
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(upload_dir(), filename))
return "", 200
我想将它存储在 postgres 的 BYTEA 列中,我不确定如何将“数据”参数绑定到插入语句
db.session.execute("""
INSERT INTO uploaded_file(id, name, type, data)
VALUES (:id, :name, :type, %(:data)s)""",
{"id": str(id),"name": file.filename,"type": "...","data": ???}
【问题讨论】:
标签: python flask flask-sqlalchemy psycopg2 werkzeug