通过按下按钮 Tkinter 打破循环

Question

我的程序在 while 循环中有很多任务要做我需要制作一个按钮来打破循环 这是一个例子：

from tkinter import *
from selenium import webdriver
from time import sleep

class screen():
    def __init__(self):
        self.no = 1

    def close(self):
        #what should i do?

    def go(self,a,b,c,d):
        self.close = Button(self.window, text=f"{d}close", width=10, height=2, command=self.close)
            self.close.grid(row=4+d,column=1,columnspan=3,padx=5, pady=5)
        driver = webdriver.Chrome(executable_path="webdriver")
        while True:
            driver.get(a)
            sleep(11)
            print("1 done")
            driver.get(b)
            sleep(5)
            print("2 done")
            driver.get(c)
            sleep(5)
            print("3 done")
            print(f"we will go to your {d}th 3 website again")
        driver.close()

    def start(self):
        a = self.Entry1.get()
        b = self.Entry2.get()
        c = self.Entry3.get()
        self.no = self.no + 1
        thread = threading.Thread(target=self.go, args=[a,b,c,self.no], daemon=True).start()

    def tkin(self):
        self.window = Tk()
        self.window.title("selenium task")
        self.label1 = Label(self.window, text="enter your 1 website")
        self.Entry1 = Entry(self.window)
        self.label2 = Label(self.window, text="enter your 2 website")
        self.Entry2 = Entry(self.window)
        self.label3 = Label(self.window, text="enter your 3 website")
        self.Entry3 = Entry(self.window)
        self.button = Button(self.window, text="start", width = 10 , height = 2 , command = self.start)
        self.label1.grid(row=1,column=1, columnspan = 3, padx=5, pady=5)
        self.Entry1.grid(row=1,column=2, columnspan = 3, padx=5, pady=5)
        self.label2.grid(row=2,column=1, columnspan = 3, padx=5, pady=5)
        self.Entry2.grid(row=2,column=2, columnspan = 3, padx=5, pady=5)
        self.label3.grid(row=3,column=1, columnspan = 3, padx=5, pady=5)
        self.Entry4.grid(row=3,column=2, columnspan = 3, padx=5, pady=5)
        self.button.grid(row=4,column=1, columnspan = 3, padx=5, pady=5)

我需要在任何网站上点击关闭按钮来打破这个循环（1 或 2 或 3 我不知道用户何时会点击）或关闭我点击关闭编号的 selenium 的方法

Answer 1

如果需要中断循环，您可以让screen.close() 方法将变量设置为True。仅当变量为True 时，循环才应运行。这是代码，添加和编辑的行相应标记：

from tkinter import *
from selenium import webdriver
from time import sleep

class screen():
    def __init__(self):
        self.no = 1
        self.break_loop = False ### ADDED LINE

    def close(self):
        self.break_loop = True ### ADDED LINE

    def go(self,a,b,c,d):
        self.close_button = Button(self.window, text=f"{d}close", width=10, height=2, command=self.close) ### EDITED LINE
        self.close_button.grid(row=4+d,column=1,columnspan=3,padx=5, pady=5) ### EDITED LINE
        driver = webdriver.Chrome(executable_path="webdriver")
        while not self.break_loop: ### EDITED LINE
            driver.get(a)
            sleep(11)
            print("1 done")
            driver.get(b)
            sleep(5)
            print("2 done")
            driver.get(c)
            sleep(5)
            print("3 done")
            print(f"we will go to your {d}th 3 website again")
        self.break_loop = False ### ADDED LINE
        driver.close()

    def start(self):
        a = self.Entry1.get()
        b = self.Entry2.get()
        c = self.Entry3.get()
        self.no = self.no + 1
        thread = threading.Thread(target=self.go, args=[a,b,c,self.no], daemon=True).start()

    def tkin(self):
        self.window = Tk()
        self.window.title("selenium task")
        self.label1 = Label(self.window, text="enter your 1 website")
        self.Entry1 = Entry(self.window)
        self.label2 = Label(self.window, text="enter your 2 website")
        self.Entry2 = Entry(self.window)
        self.label3 = Label(self.window, text="enter your 3 website")
        self.Entry3 = Entry(self.window)
        self.button = Button(self.window, text="start", width = 10 , height = 2 , command = self.start)
        self.label1.grid(row=1,column=1, columnspan = 3, padx=5, pady=5)
        self.Entry1.grid(row=1,column=2, columnspan = 3, padx=5, pady=5)
        self.label2.grid(row=2,column=1, columnspan = 3, padx=5, pady=5)
        self.Entry2.grid(row=2,column=2, columnspan = 3, padx=5, pady=5)
        self.label3.grid(row=3,column=1, columnspan = 3, padx=5, pady=5)
        self.Entry4.grid(row=3,column=2, columnspan = 3, padx=5, pady=5)
        self.button.grid(row=4,column=1, columnspan = 3, padx=5, pady=5)

我将关闭按钮重命名为close_button，这样它就不会覆盖同名的close() 方法。

按下close_button 时，self.break_loop 设置为True。只要self.break_loop 是True，循环就会运行。循环运行后，self.break_loop 再次设置回False，以便再次调用go() 方法。