尝试制作一个根据声音改变颜色的红绿灯（响亮的声音=红色，正常的声音=绿色等）

Question

我一直在尝试制作一个 Tkinter 应用程序，作为所产生声音的反馈信号灯。因此，例如，当它在图书馆里响亮时，你会得到一个红灯，但当它正常时，它会变成绿色等等。

基本上，我已经创建了一个带有画布的 Tkinter 应用程序，并在一个矩形中制作了 3 个圆圈（红绿灯），还创建了一个函数来从你的麦克风获取输入以查看声音的高低。

此代码在一个单独的文件中用于获取输入声音：

def decide_colour():

    def print_sound(indata, outdata, frames,tijd, status):
        global colour
        volume_norm = np.linalg.norm(indata)
        print(volume_norm)
        time.sleep(1)

        #set fill colour
        if volume_norm > 2 and volume_norm <4:
            colour = "yellow"
        elif volume_norm > 4:
            colour = "red"
        else:
            colour = "green"

        print(colour)

    with sd.Stream(callback=print_sound):
        sd.sleep(duration * 1000)


decide_colour()

这是应该显示它的 tkinter 应用程序：

class TrafficLights:

    def __init__(self):

        root = Tk()
        root.title("Stoplicht")
        root.configure(bg='black')
        root.geometry('460x400')

        # Frame voor widgets
        frame = Frame(root)
        frame.grid()

        self.colour = StringVar()

        # canvas voor lichten
        self.canvas = Canvas(root, width=460, height=400, bg="black")
        self.canvas.create_rectangle(190, 10, 310, 350, outline='white', fill='black')
        self.canvas.grid()

        self.oval_red = self.canvas.create_oval(200, 20, 300, 120, fill="white")

        self.oval_yellow = self.canvas.create_oval(200, 130, 300, 230, fill="white")

        self.oval_green = self.canvas.create_oval(200, 240, 300, 340, fill="white")

        # kleurbepaling voor de cirkels
        def change_color(self):

            if colour == 'red':
                self.canvas.itemconfig(self.oval_red, fill="red")
                self.canvas.itemconfig(self.oval_yellow, fill="white")
                self.canvas.itemconfig(self.oval_green, fill="white")
            elif colour == 'yellow':
                self.canvas.itemconfig(self.oval_red, fill="white")
                self.canvas.itemconfig(self.oval_yellow, fill="yellow")
                self.canvas.itemconfig(self.oval_green, fill="white")
            elif colour == 'green':
                self.canvas.itemconfig(self.oval_red, fill="white")
                self.canvas.itemconfig(self.oval_yellow, fill="white")
                self.canvas.itemconfig(self.oval_green, fill="green")

        change_color(self)

        root.after(500, change_color(self))
        #root.after(500, TrafficLights)

        root.mainloop()


while True:
    decide_colour()
    TrafficLights()

但它陷入了一个循环。并且通过摆脱while 语句，它只会打开一次。但我希望它继续运行，我希望它改变红绿灯的颜色。我已经尝试了几天，寻找答案。但我现在真的被困住了。

Answer 1

问题似乎与您的程序的组织有关。不需要while 循环。我做了一个简单的例子来说明after 应该如何工作。在after 循环中调用的函数应该从decide_colour() 函数中获取它需要的数据。在此示例中，它将是 my_count()。

from tkinter import *

class Counter(Frame):

    def __init__(self, master=None):
        self.count = 0
        super().__init__(master)
        self.grid()
        self.__create_widgets()

    def __create_widgets(self):
        self.count_label         = Label(self)
        self.count_label["text"] = str(self.count)
        self.count_label["pady"] = 5
        self.count_label.grid()


    def my_count(self):
        self.count = self.count+1
        self.count_label["text"] = str(self.count)


root = Tk()
counter = Counter(master=root)

#do you app set up here
root.title("Counter")
root.geometry('460x400')

def do_one_iteration():
    counter.my_count()
    root.after(500, do_one_iteration)
do_one_iteration()

counter.mainloop()

Answer 2

好吧，这不是我想要的答案，但它仍然是一个答案

我将代码放在一起，并进行了一些调整。

from tkinter import *
import sounddevice as sd
import numpy as np
import time

duration = 1  #


def decide_colour():
    def print_sound(indata, outdata, frames, tijd, status):
        global colour
        volume_norm = np.linalg.norm(indata)
        time.sleep(1)

        # set fill colour
        if 2 < volume_norm < 4:
            colour = "yellow"
        elif volume_norm > 4:
            colour = "red"
        else:
            colour = "green"

        print(volume_norm, colour)

    with sd.Stream(callback=print_sound):
        sd.sleep(duration * 1000)


class TrafficLights:

    def __init__(self):

        root = Tk()
        root.title("Stoplicht")
        root.configure(bg='black')
        root.geometry('460x400')

        # Frame voor widgets
        frame = Frame(root)
        frame.grid()

        self.colour = StringVar()

        # canvas voor lichten
        self.canvas = Canvas(root, width=460, height=400, bg="black")
        self.canvas.create_rectangle(190, 10, 310, 350, outline='white', fill='black')
        self.canvas.grid()

        self.oval_red = self.canvas.create_oval(200, 20, 300, 120, fill="red")
        self.oval_yellow = self.canvas.create_oval(200, 130, 300, 230, fill="white")
        self.oval_green = self.canvas.create_oval(200, 240, 300, 340, fill="white")

    def create_frame():
        decide_colour()

        if colour == 'red':
            self.canvas.itemconfig(self.oval_red, fill="red")
            self.canvas.itemconfig(self.oval_yellow, fill="white")
            self.canvas.itemconfig(self.oval_green, fill="white")
        elif colour == 'yellow':
            self.canvas.itemconfig(self.oval_red, fill="white")
            self.canvas.itemconfig(self.oval_yellow, fill="yellow")
            self.canvas.itemconfig(self.oval_green, fill="white")
        elif colour == 'green':
            self.canvas.itemconfig(self.oval_red, fill="white")
            self.canvas.itemconfig(self.oval_yellow, fill="white")
            self.canvas.itemconfig(self.oval_green, fill="green")

        create_frame()

        root.update()
        time.sleep(1)
        root.destroy()
        return


while True:
    TrafficLights()

所以现在它在一秒钟后打开一个新的主循环并破坏之前的主循环。我实际上希望它在一个主循环中更新，但不知道如何，所以如果有人知道请告诉我