在 matplotlib 中绘制图形时遇到问题

Question

我正在尝试制作一个 python 项目，它是一个员工管理系统，我在其中使用各种 python 库，如 tkinter、sqlite3（连接数据库）、matplotlib。在提议的项目中，我们可以为员工添加、查看、更新、删除和绘制图表。我面临的问题是图表。图表代码如下

from tkinter import *
from tkinter.messagebox import *
from tkinter.scrolledtext import *
from sqlite3 import *
import matplotlib.pyplot as plt

def graphback():
    graph_window.deiconify()
    main_window.withdraw

def graph():
    con = None
    try:
        con = connect(project.db)
        cursor = con.cursor()
        sql = "select * from employee"
        cursor.execute(sql)
        data = cursor.fetchall()
        name = []
        salary = []
        plt.plot(name, salary)
        plt.title("Highest Salaried Employee")
        plt.show
    except Exception as e:
        showerror("issue ", e)
        con.rollback()
    finally:
        if con is not None:
            con.close()
    

def mgraph():
    main_window.deiconify()
    graph_window.withdraw()

我在运行代码时无法获取图表。我应该怎么做才能运行代码？

Answer 1

您错过了plt.show 周围的括号，否则您不会调用该函数。

改成

from tkinter import *
from tkinter.messagebox import *
from tkinter.scrolledtext import *
from sqlite3 import *
import matplotlib.pyplot as plt

def graphback():
    graph_window.deiconify()
    main_window.withdraw

def graph():
    con = None
    try:
        con = connect(project.db)
        cursor = con.cursor()
        sql = "select * from employee"
        cursor.execute(sql)
        data = cursor.fetchall()
        name = []
        salary = []
        plt.plot(name, salary)
        plt.title("Highest Salaried Employee")
        # SEE HERE
        plt.show()
    except Exception as e:
        showerror("issue ", e)
        con.rollback()
    finally:
        if con is not None:
            con.close()
    

def mgraph():
    main_window.deiconify()
    graph_window.withdraw()