如果两行不为空，则连接它们

Question

我想将 2 行文本合并为一行，但前提是它们都不是空行。例如：

1:1 Bob drives his car.
1:2 Bob and his wife are going on a trip. 
They will have an awesome time on the beach.

我想将它们放入这样的字典中：

dict[1:1] gives me "Bob drives his car."
and dict[1:2] must give me "Bob and his wife are going on a trip.They will have an awesome time on the beach."

我知道如何解决第一个问题 (dict[1:1])，但我不知道如何将这两个句子放在一起。

或者是否有一个选项，如果一个句子后面跟着另一个句子，你可以把它们放在一行？这只是现实中的一个例子，文件包含100000行。

Answer 1

您可以这样做 - 从文件中一次读取一行，如果有空行则触发新部分的开始。

start_new_section = True
key = None
output = {}
with open('file.txt', 'r') as f:
    for line in f:
        if line == '':
            start_new_section = True
        elif start_new_section:
            words = line.split(' ')
            key = words[0]
            output[key] = ' '.join(words[1:])
            start_new_section = False
        else:
            output[key] += line

print(output)

或者相同想法的更简洁的版本：

key = None
output = {}
with open('file.txt', 'r') as f:
    for line in f:
        if not line:
            key = None
        elif key:
            output[key] += line
        else:
            key, _, output[key] = line.partition(' ')

Answer 2

解决此问题的一种可能方法是浏览文件一次，并列出以数值开头的索引。然后您可以使用索引来创建您的字典，因为您知道索引中的每 2 个数字都包含一个应该插入到字典中的项目。

Answer 3

假设文件足够小，您可以将整个内容读入内存，您可以使用正则表达式来解析块。这是example in action。

import re

with open('file.txt', 'r') as f:
    txt = f.read()

matches = re.findall(r'^(\d+:\d+) (.+?)$(?=(?:\s^\d+:\d+)|\z)', txt, flags=re.M | re.S)
d = {m[0]: m[1].replace(r'\n', '') for m in matches}