图表 barh matplotlib - 重叠条

Question

我是 matplotlib 的新用户，我对图表 barh 有疑问：重叠条。 绘制图表时，条形图重叠，我没有找到原因。在我看来，问题在于重新调整图表的大小。我重新调整它的大小，因为将来我将插入标题、图例和 x、y 描述。我尝试了一些解决方案，但我有一个解决方案！ 这是我的代码：

    import matplotlib.pyplot as plt
    import matplotlib.font_manager as fm
    from matplotlib.colors import LightSource
    from matplotlib.artist import Artist
    import numpy as np
    from decimal import *
    import datetime
    #Size
    width = 360
    height = 240
    dpi = 80.0
    colors = ['#be1e2d',
            '#666699',
            '#92d5ea',
            '#ee8310',
            '#8d10ee',
            '#5a3b16',
            '#26a4ed',
            '#f45a90',
            '#e9e744']
    #Data
    columns = ['2005','2006']
    data = [[2.6,3.5],[2, 1.5]]
    linewidth = 1
    N = len(columns)
    
    ind = np.arange(N)  
    #Re-Size
    rdata = len(data) if columns is None else len(columns)
    heightColumn = height*1.0 / (rdata) / (len(columns))
    heightColumn = heightColumn/dpi
    fig = plt.figure(1, figsize=(width/dpi,height/dpi),facecolor='w')
    ax = fig.add_axes([0.2, 0.3, 0.6, 0.5])
    #Draw
    tupleRects = ()
    idxColor = 0 
    valPositionCol = ind
    for dat in data:
        rects = plt.barh(valPositionCol, dat, heightColumn, color=colors[idxColor], alpha=0.8,  
                         linewidth=linewidth)
        valPositionCol=valPositionCol+heightColumn
        idxColor += 1
        if idxColor==9:
            idxColor = 0
        tupleRects += (rects,)
    plt.show()

谢谢

---

代码是一样的，但是我改了数据（columns[] e data[]）：

import matplotlib.pyplot as plt
import matplotlib.font_manager as fm


from matplotlib.colors import LightSource
import numpy as np
from decimal import *
import datetime
#Size
width = 360
height = 240
dpi = 80.0
colors = ['#be1e2d',
            '#666699',
            '#92d5ea',
            '#ee8310',
            '#8d10ee',
            '#5a3b16',
            '#26a4ed',
            '#f45a90',
            '#e9e744']
#Data
columns = ['2005','2006']
data = [[1.5, 1.5], [1.5,1.5], [1.5,1.5]]
linewidth = 1
N = len(columns)


ind = np.arange(N)  
#Re-Size
height_of_group = .9
   

heightColumn = height_of_group / (len(columns))
fig = plt.figure(1, figsize=(width/dpi,height/dpi),facecolor='w')
ax = fig.add_axes([0.2, 0.3, 0.6, 0.5])
#Draw


tupleRects = ()
idxColor = 0 
valPositionCol = ind
for dat in data:
    rects = plt.barh(valPositionCol, dat, heightColumn, color=colors[idxColor], alpha=0.8,  
                     linewidth=linewidth)
    valPositionCol=valPositionCol+heightColumn
    idxColor += 1
    if idxColor==9:
        idxColor = 0
    tupleRects += (rects,)
plt.show()

问题是我有可变数据，我必须找到一个稳定的算法。

Answer 1

我认为您误解了高度的含义（doc）。单位是轴单位，而不是像素。

heightColumn = height*1.0 / (rdata) / (len(columns))
heightColumn = heightColumn/dpi

到

height_of_group = .9
heightColumn = height_of_group / (len(data))
#heightColumn = heightColumn/dpi

将获得不重叠的条形，组之间只有一点额外的空间。您可以通过使height_of_group 大于或小于1 来调整组之间的间距。