在 Python 中访问附加到列表的对象属性的问题

Question

我正在尝试创建一个房间检查应用程序，将失败的房间附加到一个列表中。

一旦创建的“房间”对象被附加到空的“失败房间”列表中，我遇到的问题就是访问属性。我所能做的就是返回对象在内存中的存储位置。

class UniRoom(object):
    def __init__(self, roomNumber, balcony, carpet, bedroom, room):
        self.roomNumber = roomNumber
        self.balcony = balcony
        self.carpet = carpet
        self.bedroom = bedroom
        self.room = room

    def printResult(self): #deleted because irrelevant to question.
        


failedRooms = []
print("---------- Globe Apartments Room Checker ----------")
rooms = [UniRoom(roomNumber=input("\nPlease enter the number of the room being graded: "),
                 balcony=input("Please enter the grade of the balcony: "),
                   carpet = input("Please enter the grade of the carpet: "),
                   bedroom = input("Please enter the grade of the bedroom: "),
                   room = input("Please enter the final grade of the room: ").upper()) for i in range(3)]

for r in rooms:
    r.printResult()
    if r.room == 'FAIL':
        print("This room has failed inspection")
        failedRooms.append(r)

print(failedRooms)

抱歉，如果我没有遵循发布格式。我是 stackoverflow 的新手，正在尝试制作我的第一个 Python 项目（相对较新的 Python 约 2 个月的经验，主要用于做理论）

不胜感激。谢谢！

Answer 1

您正在尝试打印 failedRooms 数组，而不是数组中的 UniRoom 实例。您可以使用 [] 在 failedRooms 中指定特定的 UniRoom，如下所示：

print(failedRooms[0])

虽然它仍然只是一个对象的内存地址。要访问 UniRoom 中的属性，您可以执行类似的操作（稍微修改代码版本）。我正在遍历添加到 failedRooms 列表中的每个失败房间，并打印每个房间的详细信息：

class UniRoom(object):
    def __init__(self, room_number, balcony, carpet, bedroom, room):
        self.room_number = room_number
        self.balcony = balcony
        self.carpet = carpet
        self.bedroom = bedroom
        self.room = room

    def print_result(self):  # deleted because irrelevant to question.
        print(self)


failedRooms = []
print("---------- Globe Apartments Room Checker ----------")
rooms = [UniRoom(room_number=i,
                 balcony=90,
                 carpet=80,
                 bedroom=70,
                 room='FAIL') for i in range(3)]

for r in rooms:
    r.print_result()
    if r.room == 'FAIL':
        print("This room has failed inspection")
        failedRooms.append(r)

for failed_room in failedRooms:
    print('room_number: {}'.format(failed_room.room_number))
    print('balcony: {}'.format(failed_room.balcony))
    print('carpet: {}'.format(failed_room.carpet))
    print('bedroom: {}'.format(failed_room.bedroom))
    print('room: {}'.format(failed_room.room))