python随机dict键，并访问它[关闭]答案

【问题标题】：python random dict key, and access it [closed]python随机dict键，并访问它[关闭]
【发布时间】：2017-07-04 19:53:01
【问题描述】：

import random


Cards = {
    "Spade": ["2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King", "Ace"],
    "Diamond": ["2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King", "Ace"],
    "Club": ["2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King", "Ace"],
    "Heart": ["2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King", "Ace"]

}

for _ in range(55):
    r = random.sample(list(Cards), 1)
    print(r[0])

我尝试了很多，但无法弄清楚。我在访问密钥的值时遇到问题

【问题讨论】：

标签： python list dictionary random key

【解决方案1】：

这样的？

>>> random.choice(list(Cards))
'Heart'

然后是一张随机牌：

>>> suit = random.choice(list(Cards))
>>> card = random.choice(Cards[suit])
>>> card, suit
('King', 'Heart')

【讨论】：

是的，然后访问值，r = random.choice(Cards.keys()) print(r[1])