【发布时间】:2017-11-22 12:18:58
【问题描述】:
我正在尝试使用 python 请求获得响应。但是我面临 SSL 握手错误。我尝试了这里发布的许多解决方案,但似乎没有任何效果。请帮忙。提前致谢
这是代码:
import requests
url = "https://androidappsapk.co/download/com.facebook.katana"
requests.get(url, verify = False)
这是我得到的错误:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/site-packages/requests/api.py", line 55, in get
return request('get', url, **kwargs)
File "/usr/local/lib/python2.7/site-packages/requests/api.py", line 44, in request
return session.request(method=method, url=url, **kwargs)
File "/usr/local/lib/python2.7/site-packages/requests/sessions.py", line 456, in request
resp = self.send(prep, **send_kwargs)
File "/usr/local/lib/python2.7/site-packages/requests/sessions.py", line 559, in send
r = adapter.send(request, **kwargs)
File "/usr/local/lib/python2.7/site-packages/requests/adapters.py", line 382, in send
raise SSLError(e, request=request)
requests.exceptions.SSLError: [SSL: SSLV3_ALERT_HANDSHAKE_FAILURE] sslv3 alert handshake failure (_ssl.c:590)
附: - 我正在使用 Python 2.7.11
【问题讨论】:
-
服务器似乎有 problems 和 OpenSSL 0.98 客户端。您使用什么 OpenSSL 版本?
-
我使用的是 OpenSSL 1.0.0 版
标签: python python-2.7 python-requests