在 DataFrame 中查找第二次出现的正则表达式

Question

我在数据框中有一个字符串列，我想从中提取一个速率，这是最后一次出现的反斜杠。

 After so many requests, this is Bretagne. She was the last surviving 9/11 search dog, and our second ever 14/10. RIP* 

我想得到14/10

Answer 1

尝试使用此代码获取这句话中所有日期的列表

import re
re.findall(r"\d+/\d+","After so many requests, this is Bretagne. She was the last surviving 9/11 search dog, and our second ever 14/10. RIP* ")

要获得第二个，只需选择此列表中的第二个项目

Answer 2

这个正则表达式有效：

>>> s = "After so many requests, this is Bretagne. She was the last surviving 9/11 search dog, and our second ever 14/10. RIP*"
>>> re.findall("\d+/(?=[^/]*$)\d+", s)
['14/10']