【发布时间】:2020-07-18 18:12:54
【问题描述】:
我是 Python 新手,正在努力遍历两个不同数据集的行和列,以生成一个值数组。
我有两个数据框(parameterMatrix 和growthRates);一个显示了一系列物种及其相互作用的强度,另一个显示了每个物种的生长速度。
参数矩阵:
herbivores youngScrub matureScrub sapling matureTree grassHerbs
herbivores 0.0 0.02 0 0.05 0 0.5
youngScrub -0.2 0.00 0 0.00 0 0.0
matureScrub 0.0 0.00 0 0.00 0 0.0
sapling -0.2 0.00 0 0.00 0 0.0
matureTree 0.0 0.00 0 0.00 0 0.0
grassHerbs -5.0 0.00 0 0.00 0 0.0
增长率:
herbivores youngScrub matureScrub sapling matureTree grassHerbs
0 0.1 0 0.1 0.1 0 0.2
我正在尝试为六个物种中的每一个生成一组值,最终可用于计算每个物种随时间的变化率。我已经手动写出了每个方程(见下文),但我想知道是否有更快的方法来做到这一点,例如通过循环遍历这些数据帧中的每一个。
def ecoNetwork(X, t=0):
num_herbivores = X[0]
num_youngScrub = X[1]
num_matureScrub = X[2]
num_sapling = X[3]
num_matureTree = X[4]
num_grassHerb = X[5]
return np.array([
# herbivores
(growthRates['herbivores'][0])*num_herbivores + (parameterMatrix['herbivores']['herbivores']*num_herbivores*num_herbivores)
+ (parameterMatrix['herbivores']['youngScrub']*num_herbivores*num_youngScrub)
+ (parameterMatrix['herbivores']['matureScrub']*num_herbivores*num_matureScrub)
+ (parameterMatrix['herbivores']['sapling']*num_herbivores*num_sapling)
+ (parameterMatrix['herbivores']['matureTree']*num_herbivores*num_matureTree)
+ (parameterMatrix['herbivores']['grassHerbs']*num_herbivores*num_grassHerb)
,
# young scrub (X1)
(growthRates['youngScrub'][0])*num_youngScrub + (parameterMatrix['youngScrub']['herbivores']*num_youngScrub*num_herbivores)
+ (parameterMatrix['youngScrub']['youngScrub']*num_youngScrub*num_youngScrub)
+ (parameterMatrix['youngScrub']['matureScrub']*num_youngScrub*num_matureScrub)
+ (parameterMatrix['youngScrub']['sapling']*num_youngScrub*num_sapling)
+ (parameterMatrix['youngScrub']['matureTree']*num_youngScrub*num_matureTree)
+ (parameterMatrix['youngScrub']['grassHerbs']*num_youngScrub*num_grassHerb)
,
# mature scrub
(growthRates['matureScrub'][0])*num_matureScrub + (parameterMatrix['matureScrub']['herbivores']*num_matureScrub*num_herbivores)
+ (parameterMatrix['matureScrub']['youngScrub']*num_matureScrub*num_youngScrub)
+ (parameterMatrix['matureScrub']['matureScrub']*num_matureScrub*num_matureScrub)
+ (parameterMatrix['matureScrub']['sapling']*num_matureScrub*num_sapling)
+ (parameterMatrix['matureScrub']['matureTree']*num_matureScrub*num_matureTree)
+ (parameterMatrix['matureScrub']['grassHerbs']*num_matureScrub*num_grassHerb)
,
# saplings
(growthRates['sapling'][0])*num_sapling + (parameterMatrix['sapling']['herbivores']*num_sapling*num_herbivores)
+ (parameterMatrix['sapling']['youngScrub']*num_sapling*num_youngScrub)
+ (parameterMatrix['sapling']['matureScrub']*num_sapling*num_matureScrub)
+ (parameterMatrix['sapling']['sapling']*num_sapling*num_sapling)
+ (parameterMatrix['sapling']['matureTree']*num_sapling*num_matureTree)
+ (parameterMatrix['sapling']['grassHerbs']*num_sapling*num_grassHerb)
,
# mature trees
(growthRates['matureTree'][0])*num_matureTree + (parameterMatrix['matureTree']['herbivores']*num_matureTree*num_herbivores)
+ (parameterMatrix['matureTree']['youngScrub']*num_matureTree*num_youngScrub)
+ (parameterMatrix['matureTree']['matureScrub']*num_matureTree*num_matureScrub)
+ (parameterMatrix['matureTree']['sapling']*num_matureTree*num_sapling)
+ (parameterMatrix['matureTree']['matureTree']*num_matureTree*num_matureTree)
+ (parameterMatrix['matureTree']['grassHerbs']*num_matureTree*num_grassHerb)
,
# grass & herbaceous plants
(growthRates['grassHerbs'][0])*num_grassHerb + (parameterMatrix['grassHerbs']['herbivores']*num_grassHerb*num_herbivores)
+ (parameterMatrix['grassHerbs']['youngScrub']*num_grassHerb*num_youngScrub)
+ (parameterMatrix['grassHerbs']['matureScrub']*num_grassHerb*num_matureScrub)
+ (parameterMatrix['grassHerbs']['sapling']*num_grassHerb*num_sapling)
+ (parameterMatrix['grassHerbs']['matureTree']*num_grassHerb*num_matureTree)
+ (parameterMatrix['grassHerbs']['grassHerbs']*num_grassHerb*num_grassHerb)
])
# time points
t = np.linspace(0, 50)
# Initial conditions
X0=np.empty(6)
X0[0]= 10
X0[1] = 30
X0[2] = 50
X0[3] = 70
X0[4] = 90
X0[5] = 110
X0 = np.array([X0[0], X0[1], X0[2], X0[3], X0[4], X0[5]])
# Integrate the ODEs
X = integrate.odeint(ecoNetwork, X0, t)
这可能吗?如果可以,最好的方法是什么?
【问题讨论】:
-
请扩展返回的 numpy 数组以显示至少第二个物种。您是在尝试将所有物种加在一起还是要列出新元素?此外,
np.sum似乎是多余的,因为每次添加都使用标量值。最后,显示如何调用此方法。 -
感谢您的反馈;我已经编辑了我的问题以包含这些组件。我正在尝试对六个物种中的每一个应用一个方程,并将结果添加到一个新数组中。
标签: python pandas loops dataframe