Django 为同一子类别生成多个 url

Question

在我的应用程序中，有一个具有 ForeignKey 关系的类别和子类别列表。说，有：

• 与 Category1 相关的 Subcategory1
• 与 Category2 相关的 Subcategory2

我希望获得以下子类别网址：

• http://127.0.0.1:8000/cat1/subcat1
• http://127.0.0.1:8000/cat2/subcat2

这些网址工作正常。但是，django 也会生成这些我不需要的 url：

• http://127.0.0.1:8000/cat1/subcat2
• http://127.0.0.1:8000/cat2/subcat1

为什么它们会出现在我的应用中？我该如何摆脱它们？提前致谢！

models.py:

class Category(models.Model):
    categoryslug = models.SlugField(max_length=200, default="",unique=True)

    def get_absolute_url(self):
        return reverse("showrooms_by_category",kwargs={'categoryslug': str(self.categoryslug)})

class Subcategory(models.Model):
    subcategoryslug = models.SlugField(max_length=200, default="",unique=True)
    category = models.ForeignKey('Category', related_name='subcategories', 
    null=True, blank=True, on_delete = models.CASCADE)

    def get_absolute_url(self):
        return reverse("showrooms_by_subcategory",
        kwargs={'categoryslug': str(self.category.categoryslug), 'subcategoryslug': str(self.subcategoryslug)})

views.py：

class ShowroomCategoryView(DetailView):
    model = Category
    context_object_name = 'showrooms_by_category'
    template_name = "website/category.html"
    slug_field = 'categoryslug'
    slug_url_kwarg = 'categoryslug'


class ShowroomSubcategoryView(DetailView):
    model = Subcategory
    context_object_name = 'showrooms_by_subcategory'
    template_name = "website/subcategory.html"
    slug_field = 'subcategoryslug'
    slug_url_kwarg = 'subcategoryslug'

urls.py:

urlpatterns = [
    path('<slug:categoryslug>/<slug:subcategoryslug>/', views.ShowroomSubcategoryView.as_view(), name='showrooms_by_subcategory'),
    path('<slug:categoryslug>/', views.ShowroomCategoryView.as_view(), name='showrooms_by_category'),
]

Answer 1

我认为原因是foreign_key。因此，我认为您可以使用一对一的字段来获取目标，例如：

subcategoryslug = models.SlugField(max_length=200, default="",unique=True)
category = models.OneToOneField('Category', related_name='subcategories',null=True, blank=True, on_delete = models.CASCADE)

*注意：- 请理解其背后的逻辑。为此，请进行更多研究。