【问题标题】:How to calculate the distance between two points using Euclidean distance?如何使用欧几里得距离计算两点之间的距离?
【发布时间】:2020-09-25 20:39:36
【问题描述】:

答案是here

我在笛卡尔平面上有以下几点

points = [(4, 5), (-0, 2), (4, 7), (1, -3), (3, -2), (4, 5), (3, 2), (5, 7), (-5, 7), (2, 2), (-4, 5), (0, -2), (-4, 7), (-1, 3), (-3, 2), (-4, -5), (-3, 2), (5, 7), (5, 7), (2, 2), (9, 9), (-8, -9)]

我需要使用欧几里得距离找到离中心最近的点。

到目前为止,我已经这样做了:

import math
euclidean_distance=[]
distance = math.sqrt(sum([((x+y)**2) for (x,y) in points]))

for (x,y) in points:
    int(distance)
    euclidean_distance.append(distance)

min_distance=min(euclidean_distance)

print(distance)
print(euclidean_distance)
print(min_distance)

结果是:

38.71692136521188
[38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188]
38.71692136521188

为什么不计算列表中每个点的欧几里得距离?

【问题讨论】:

  • euclidean_distance.append(distance):您在列表中添加了 n 次相同的值 distance,并且此值 distance 在循环期间不会更改。您可能希望将distance 定义为一个函数而不是单个值。
  • 这是sqrt(x**2 + y**2),而不是(x+y)**2
  • 如果你运行 python >= 3.8,数学模块有一个dist 函数你可以使用。这是link

标签: python list euclidean-distance cartesian-coordinates


【解决方案1】:

最后我做到了并为我工作:

import math

distance_points=[]

def euclidean_distance (points):
    return math.sqrt((x**2+y**2))

for (x,y) in (points): 
    distance=euclidean_distance(points)
    distance_points.append(distance)


print(distance_points)

【讨论】:

  • 那会爆炸的——你是说euclidean_distance(x, y)然后distance=euclidean_distance(x, y)
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