当我输入双精度时，nextDouble() 会引发 InputMismatchException

Question

import java.util.*;

class Averager
{
    public static double unlimited()
    {
        int count = 0;
        double sum = 0;
        Scanner scan = new Scanner(System.in);
        while(scan.hasNext())
        {
            double d = scan.nextDouble();
            sum += d;
            count++;
        }
        double ave = sum/count;
        return ave;
    }

    public static void main(String[] args) {
        System.out.println(unlimited()+"\n");
    }
}

当我使用整数时没有错误，但如果我使用带有点的数字，则会出现错误。

$ javac Averager.java; java Averager
0.5
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:840)
    at java.util.Scanner.next(Scanner.java:1461)
    at java.util.Scanner.nextDouble(Scanner.java:2387)
    at Averager.unlimited(Averager.java:12)
    at Averager.main(Averager.java:21)

据我所知，0.5 应该被 double 覆盖。如果不是，请有人纠正我。

Answer 1

它可能取决于语言环境。十进制数字例如在瑞典写成 0,5。

更改您的代码，使其显示例如：

Scanner scan = new Scanner(System.in);
scan.useLocale(Locale.US);

Answer 2

This worked for me, changing the locale did not.

  Scanner sc = new Scanner(System.in);
  // val = sc.nextDouble(); - crashes with java.util.NoSuchElementException
  // If Java crashes with legal Java code, wrap the call in a hasNextLine() test
  if (sc.hasNextLine())
  {
    val = sc.nextDouble();
  }

java.util.NoSuchElementException: No line found