【问题标题】:Sorting an array by its values based on two arrays基于两个数组按其值对数组进行排序
【发布时间】:2020-03-29 22:42:19
【问题描述】:

我目前有2个阵列,电源和能量:

int[] power = [20, 10, 50, 10, 30, 5];
powerIndex     0   1   2   3   4   5
int[] energy = [20, 5, 15, 3, 10, 30];
energyIndex    0   1   2   3   4   5

我想得到一个功率数组的索引排序的数组(从最低到最高),如果功率数相同,则使用较少能量的功率应该获得第一个位置。所以基本上我想要的输出是:

int[] result = [5, 3, 1, 0, 4, 2]

这是我目前的代码:

        int[] result = new int[power.length];
        int answerIndex = 0;
        int tempSmallest = Integer.MAX_VALUE;
        int lastNumberSaved = 0;
        int posWithSmallerPower = 0;


        while (answerIndex < power.length) {

            for (int i = 0; i < power.length; i++) {
                int current = power[i];
                if (tempSmallest > current && current > lastNumberSaved) {
                    tempSmallest = current;
                    posWithSmallerPower = i;
                }

                if (tempSmallest >= current && current > lastNumberSaved) {
                    if (current != lastNumberSaved && energy[posWithSmallerPower] > energy[i]) {
                        tempSmallest = current;
                        posWithSmallerPower = i;
                    }
                }
            }
            answer[answerIndex] = posWithSmallerPower;
            answerIndex++;
            lastNumberSaved = tempSmallest;
            tempSmallest = Integer.MAX_VALUE;
        }

        return answer;

我得到了什么:[5, 3, 0, 4, 2, 2]。 再说一次,我应该得到什么:[5, 3, 1, 0, 4, 2]

我在处理具有相同数字的权力时遇到了麻烦。我确实通过它们的能量在第二个数组中比较了它们,实际上我首先得到了索引 3 中的幂,但随后代码完全忘记了也具有相同数字 (10) 的第二幂。

我如何实现这一目标?谢谢!

【问题讨论】:

  • 似乎是大学作业。您的代码没有问题。你需要思考你想要达到的目标。在一张纸上画出草图,然后开始编码。
  • @brainless-coder 谢谢!我在大约 5-6 小时后才发了这篇文章。我完全拒绝寻求帮助,直到我真的厌倦了尝试无数的“解决方案”,这些“解决方案”似乎让我更加远离结果。我很感激你的意图,和平!

标签: java arrays sorting indexing


【解决方案1】:

list.sort() 中使用内联Comparator&lt;T&gt; 来比较两个powerEnergyIndex。

import java.util.ArrayList;
import java.util.List;

public class MainApplication {
    public static void main(String[] args) {
        int[] power = {20, 10, 50, 10, 30, 5};

        int[] energy = {20, 5, 15, 3, 10, 30};

        List<PowerEnergyIndex> powerEnergyIndices = new ArrayList<>();

        for(int i=0;i<power.length;i++) {
            powerEnergyIndices.add(new PowerEnergyIndex(power[i],energy[i],i));
        }

        powerEnergyIndices.sort((p1, p2)-> {
            if(p1.power!=p2.power) {
                return p1.power-p2.power;
            }
            return p1.energy-p2.energy;
        });

        int[] result = powerEnergyIndices.stream()
                                            .map(powerEnergyIndex -> powerEnergyIndex.index)
                                            .mapToInt(x->x)
                                            .toArray();

        for(int i:result) {
            System.out.print(i + " ");
        }



    }

    static class PowerEnergyIndex {
        private int power;
        private int energy;
        private int index;

        public PowerEnergyIndex(final int power, final int energy, final int index) {
            this.power = power;
            this.energy = energy;
            this.index = index;
        }
    }
}

哪个输出 5 3 1 0 4 2

【讨论】:

    【解决方案2】:

    对于实现Comparable 接口的临时数据结构来说,这似乎是一个很好的用例。 javadoc for Comparable 解释了它的工作原理,但这是一个示例:

    import java.util.ArrayList;
    import java.util.Collections;
    import java.util.List;
    import java.util.stream.Collectors;
    
    public final class Main {
    
        private static class Entry implements Comparable<Entry> {
            private final int power;
            private final int energy;
            private final int index;
    
            public Entry(int power, int energy, int index) {
                this.power = power;
                this.energy = energy;
                this.index = index;
            }
    
            @Override
            public int compareTo(Entry o) {
                if (this.power != o.power) {
                    return this.power - o.power;
                }
                return this.energy - o.energy;
            }
        }
    
        public static void main(String[] args) {
            int[] power = {20, 10, 50, 10, 30, 5};
            int[] energy = {20, 5, 15, 3, 10, 30};
    
            List<Entry> entries = new ArrayList<>();
            for (int i = 0; i < power.length; i++) {
                entries.add(new Entry(power[i], energy[i], i));
            }
    
            Collections.sort(entries);
            List<Integer> result = entries.stream()
                    .map(entry -> entry.index)
                    .collect(Collectors.toList());
            System.out.println(result);
        }
    }
    

    哪些输出:

    [5, 3, 1, 0, 4, 2]
    

    【讨论】:

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