Python 字符串操作 - 拆分、切片、从 HEX 转换为 DEC

Question

我有以下字符串：

s = "0015CB,0,0,01,006D,0016CF1,4,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00F4E7D,1,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0008184,8,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA704,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0014EC8,2,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FAEEA,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FADE9,5,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA5A5,3,000D"

Selcuk 在000D的每次迭代中帮助拆分此值，因此提取的第一个值是0016CF1,4

现在我需要帮助将这个值的第一部分从十六进制转换为十进制，并将逗号后面的数字保留原样。所以它将是93425,4 或93425 4

到目前为止，我有以下内容并且它可以工作，但不是很优雅，请有人帮忙使它更高效/更清洁。谢谢。

my_list = [e[-9:] for e in s.split(",000D")]
print(my_list)

# Output = ['0016CF1,4', '00F4E7D,1', '0008184,8', '00FA704,9', '0014EC8,2', '00FAEEA,9', '00FADE9,5', '00FA5A5,3', '']


# for testing print the first value from the list [0]
# output = 0016CF1,4

print(my_list[0])

# save my_list in a string called list and remove the comma and check digit
# output = 0016CF1

list=str(my_list)
result = [e[-7:] for e in list.split(",")]
print(result[0])

# convert the first value from HEX to DEC
# output= 93425

res1 = int(result[0],16)
print(res1)

#  get the checkdigit for the first value in the list
checkdigit = [f[-1:] for f in s.split(",000D")]
print(checkdigit[0])

# output = 4

#  join res1 and checkdigit

print(res1,checkdigit[0])

# output = 93425 4

理想情况下，我希望在循环中使用上述内容，以便原始列表中的所有值都像上面的示例第一个值一样转换。谢谢

Answer 1

这是一个非常紧凑的解决方案：

my_list = ['0016CF1,4', '00F4E7D,1', '0008184,8', '00FA704,9',
           '0014EC8,2', '00FAEEA,9', '00FADE9,5', '00FA5A5,3']

result = [f'{int(x[:-2], 16)} {x[-1]}' for x in my_list]

这是result的最终内容：

['93425 4', '1003133 1', '33156 8', '1025796 9',
 '85704 2', '1027818 9', '1027561 5', '1025445 3']