Python - 如何在 Python 中将变量从一种方法传递到另一种方法？

Question

我四处寻找这样的问题。我见过类似的问题，但没有什么能真正帮助我。我正在尝试将选择变量从方法 rollDice() 传递给方法 main()。这是我到目前为止所得到的：

import random
import os
import sys

def startGame():
     answer = input('Do you want to play Super Dice Roll?\nEnter 1 for Yes\nEnter 2 for No\n'
     os.system('cls')
     if (answer == '1'):
          rollDice()
     elif(answer == '2'):
          print('Thank you for playing!')
     else:
          print('That isn/t a valid selection.')
          StartGame()

def rollDice():
     start = input('Press Enter to roll dice.')
     os.system('cls')
     dice = sum(random.randint(1,6) for x in range (2))
     print('you rolled ',dice,'\n')
     choice = input('Do you want to play again?\nEnter 1 for Yes\nEnter 2 for No.\n)
     return choice

def main():
     startGame()
     while (choice == '1'):
          startGame()
     print('Thank you for playing')

print('!~!~!~!~WELCOME TO SUPER DICE ROLL~!~!~!~!~\n')
main()

我知道我这里可能还有其他多余的东西，或者我可能需要修复，但我现在只是在处理这个问题。我不确定如何将选择变量传递给 main() 方法。我尝试将选择 == rollDice() 放在 main() 方法中，但没有奏效。我主要做 SQL 工作，但想开始学习 Python，我发现一个网站有 5 个初学者任务，但几乎没有说明。这是任务一。

Answer 1

您需要将函数的返回值放入一个变量中才能对其进行评估（我还纠正了您代码中的一些错误，主要是拼写错误）：

import random
import os

def startGame():
    answer = input('Do you want to play Super Dice Roll?\nEnter 1 for Yes\nEnter 2 for No\n')
    os.system('cls')
    while answer == '1':
        answer = rollDice()
    if answer == '2':
        print('Thank you for playing!')
    else:
        print('That isn/t a valid selection.')
        startGame()

def rollDice():
    input('Press Enter to roll dice.')
    os.system('cls')
    dice = sum(random.randint(1,6) for x in range (2))
    print('you rolled ', dice, '\n')
    choice = input('Do you want to play again?\nEnter 1 for Yes\nEnter 2 for No.\n')
    return choice

def main():
    print('!~!~!~!~WELCOME TO SUPER DICE ROLL~!~!~!~!~\n')
    startGame()
    print('Thank you for playing')


main()