【发布时间】:2021-06-07 16:24:36
【问题描述】:
获取仅影响我的检索薪水方法的主要方法错误我不确定如何解决该问题我添加了特定项目,但我无法让错误消失。是我的程序中唯一出现错误并且我无法继续的事情。图片包含我现在遇到的唯一问题
"错误:类中找不到主方法,请将主方法定义为: 公共静态无效主要(字符串 [] 参数) 或者 JavaFX 应用程序类必须扩展 javafx.application.Application"
public class finalproject {
public static class employeeCase {
EMPLOYEE[] employees;
int AMOUNT;
employeeCase(){
employees = new EMPLOYEE[100];
AMOUNT = 0;
}
private void loadEmployee() {
String ID = null;
int SALARY = 0;
Scanner sc = new Scanner(System.in);
System.out.println(" ");
System.out.println("How many employees do you want to load?: ");
int num = sc.nextInt();
for(int i = 0; i < num; i++){
// Display parallel arrays
System.out.println(" ");
System.out.println("Name: " + employees[i] + " " + "ID: " + ID + " " + "Salary: " + SALARY);
sc.close();
}
}
private int addEmployee() {
Scanner sc = new Scanner(System.in);
System.out.println(" ");
System.out.println("How many employees do you want to enter?: ");
AMOUNT = 0;
AMOUNT = sc.nextInt();
String Again1 = "no";
String Fname;
String ID;
int SALARY = 0;
do {
for(int i = 0; i < AMOUNT; i++) {
System.out.printf("Enter employee's first name: ");
Fname = sc.nextLine();
System.out.printf("Enter employee ID (5 digits): ");
ID = sc.next();
System.out.printf("Enter employee salary: ");
SALARY = sc.nextInt();
System.out.println(" ");
this.employees[this.AMOUNT] = new EMPLOYEE(Fname, ID, SALARY);
this.AMOUNT++;
sc.close();
} } while (Again1.equalsIgnoreCase("yes"));
return SALARY;
}
private void displayEmployee() {
for(int i = 0; i < AMOUNT; i++){
// Display parallel arrays
System.out.println(" ");
System.out.println(this.employees[i]);
}
}
private void retrieveSpecific() {
Scanner sc = new Scanner(System.in);
System.out.println(" ");
System.out.println("Enter employee ID: ");
String id = sc.next();
//Search for ID in all the stored employees
for(int i=0; i<this.AMOUNT; i++) {
if(id.contentEquals(this.employees[i].ID)) {
System.out.println(this.employees[i]);
sc.close();
}}}
private void retrieveSalary() {
Scanner scan = new Scanner(System.in);
System.out.println(" ");
System.out.println("Enter lowest employee salary: ");
int LSALARY = scan.nextInt();
System.out.println(" ");
System.out.println("Enter highest employee salary: ");
int HSALARY = scan.nextInt();
for(int i = 0; i < AMOUNT; i++) {
if(employees[i].SALARY >= LSALARY & employees[i].SALARY <= HSALARY) {
System.out.println(employees[i]);
scan.close();}}
}
public static void main(String[] args) {
employeeCase EmployeeData = new employeeCase();
Scanner sc = new Scanner(System.in);
int Select = 0;
do {
displayMenu();
System.out.print("Input your selection from the menu: ");
Select = sc.nextInt();
switch (Select) {
case 1 : EmployeeData.loadEmployee();
break;
case 2 : EmployeeData.addEmployee();
break;
case 3 : EmployeeData.displayEmployee();
break;
case 4 : EmployeeData.retrieveSpecific();
break;
case 5 : EmployeeData.retrieveSalary();
break;
case 6 : System.out.println("Thank you, goodbye!");
break;
default : System.err.println("Invalid Input");
break;
}
} while (Select != 6);
sc.close();
}
public static void displayMenu() {
System.out.println(" MENU");
System.out.println("============================================");
System.out.println("1: Load employees' data");
System.out.println("2: Add new employee");
System.out.println("3: Display all employees");
System.out.println("4: Retrieve specfic employee data");
System.out.println("5: Retrieve employee based on salary range");
System.out.println("6: Exit program");
}
}}
【问题讨论】:
-
主要方法是静态的!!
-
认真对待错误信息:你没有
public static void main (String[] args)方法! -
好的,我现在已经编辑了主要方法,但只有我的 retreivesalary 不适用于案例
标签: java arrays object methods