编写一个程序，将名称存储为字符串，将数字存储为 11 个玩家的整数

Question

我如何从两个游戏的每个玩家那里获得平均分？

编写一个程序，将姓名存储为字符串，并将数字存储为团队中 11 名球员的整数。你的程序应该显示/输出每个玩家在两场比赛中的平均得分。

尼克 (34)、乔伊 (33)、肯 (24)、瑞恩 (11)、乔什 (3)、西蒙 (6)、狄龙 (10)、迈克 (28) 和卡梅隆 (5)。

第一局：4、3、3、2、4、5、6、6、7、7、8。 第二局：8、4、3、3、5、5、7、8、8、9、5。

import java.util.Scanner;
import java.util.Arrays;
public class BasketballStats {

public static void main(String[] args) {
    // TODO Auto-generated method stub

    int[] jerseyNumber = {34, 33, 24, 11, 3, 13, 6, 4, 28, 10};

    String[] playerName = {"Jim", "Joe", "Ken", "James", "John", "Bud", 
"Clark", "Barry", "Jose", "Paul"};

    int[] game1 = new int[11];
    int[] game2 = new int[11];

    for (int i = 0; i < 10; i++)

            System.out.printf("Number %d: %s \n" , jerseyNumber[i], 
playerName[i]);
}

public void setGame1Score() {

int[] jerseyNumber = {34, 33, 24, 11, 3, 13, 6, 4, 28, 10};
String[] playerName = {"Jim", "Joe", "Ken", "James", "John", "Bud", "Clark", 
"Barry", "Jose", "Paul"};

Scanner input = new Scanner (System.in);
    for (int i = 0; i < 10; i++) {
        System.out.println("For game 1, how many points does he score?");
        int game2 = input.nextInt();

} 

    }

}

Answer 1

当您处理单个数组中的数据属性时，事情往往会变得非常乏味。从概念上讲，在这种情况下，将玩家视为一个唯一的对象来保存他们的姓名、号码和分数更有意义。

public class Player {
    private String name;
    private int number;
    private int scores[];
    private int currentGame = 0;

    public Player(String name, int number, int numGames) {
       this.name = name;
       this.number = number;
       this.scores = new int[numGames];
    }
    // Getters and Setters
    public String getName() { return name; } // Required

    public void addScore(int score) { 
        if (currentGame < scores.length) {
            scores[currentGame++] = score;
        }

    }

    public int getAverage() {
        int total = 0;
        for (int i = 0; i < currentGame; i++) {
           total += scores[i];
        }
        return total / currentGame;
    }

    @Override
    public String toString() {
        return String.format("%s (%s) : avg %d", name, number, getAverage());
    }
}

然后，您可以使用玩家的姓名、号码和玩过的游戏数来实例化玩家。但是，您可能喜欢将 Player 类视为单个游戏，并拥有一个描述每个游戏本身的对象；由10名玩家组成。该对象缺少名称和数字属性的 getter/setter。

然后您可以创建一个数组来保存游戏的所有数据。如果您计划进行多场比赛，您可能希望获得一系列分数，而不是每个玩家的单个分数。

public static final String[] playerName = {"Jim", "Joe", "Ken", "James", "John", "Bud", 
"Clark", "Barry", "Jose", "Paul"}; 
public static final int[] jerseyNumber = {34, 33, 24, 11, 3, 13, 6, 4, 28, 10};

public Player[] createGame(int numGames) {
    Player[] players = new Player[10];

    for (int i = 0; i < 10; i++) {
        players[i] = new Player(playerName[i], jerseyNumber[i], numGames);
    }

    return players;
} 

然后你什么时候需要以某种方式获得分数。

public void getScore(Player[] players, int numGames) {
    Scanner input = new Scanner(System.in);
    for (int i = 0; i < numGames; i++) {
        System.out.println("Game " + i);
        for (Player player : players) {
            System.out.print(player.getName() + " : ");
            player.addScore(input.nextInt());
        }
    }
}

public void getAverage(Player[] players) {
    for (Player player : players) {
        System.out.println(player.toString());
    }
}