classs = input("Class [1, 2 or 3] - ")
if clas
data = f.readlines()
for le:
print(line)
found = True
if found == False:
print("False")
这是一个典型的打印输出：
John = 10
John = 6
John = 4
我需要能够仅通过使用 10, 4, 6 来创建平均值，因为我需要知道一种方法来隔离其余部分并允许数字继续以创建平均分数。
希望有人明白这一点并能够提供帮助！
提前致谢！
【问题讨论】：
标签： python
如果每个行的格式都相同，可以使用string.split并强制转换为int：
classs = input("Class [1, 2 or 3] - ")
l = []
if classs =='1':
name = input("What is your name? - ")
datafile = '1.txt'
found = False
with open(datafile, 'r') as f:
data = f.readlines()
for line in data:
if name in line:
print(line)
l.append(int(line.split()[2]))
found = True
if found == False:
print("False")
然后遍历数字列表并获得平均值，例如：
total = 0
num = 0
for x in l:
total = total + x
num = num + 1
print(total/num)
【讨论】：
list，您将接管builtin function list() 并使您的代码更加混乱。
一种方法是从您的列表中提取每个玩家的最后 3 个数字（我假设您只需要 3 个，如果不需要，此代码可以更改更多）
Class = input("Class: ")
dataList = []
file = open('class ' + str(Class) + '.txt', "r")
for line in file:
count = 0
record = line
studentList = record.split(': ')
score = studentList[1].strip('\n')
studentList = [studentList[0], score]
if len(dataList) == 0:
dataList.append(studentList)
else:
while count < len(dataList):
if studentList[0] == dataList[count][0]:
if len(dataList[count]) == 4:
dataList[count][3] = dataList[count][2]
dataList[count][2] = dataList[count][1]
dataList[count][1] = score
break
dataList[count].append(score)
break
elif count == len(dataList) - 1:
dataList.append(studentList)
break
count = count + 1
这会给你一个二维数组。每个较小的数组都将在索引 0 处包含人员姓名，并且在索引 1,2 和 3 处包含三个数字。现在你有了这些，你可以简单地计算出平均值。
AverageScore = []
# this is the array where the student' record (name and highest score) is saved
# in a list
count = 0
while count < len(dataList):
entry = []
# this is whre each student name and score will be temporarily held
entry.append(dataList[count][0])
# this makes it so the array 'entry' contains the name of every student
Sum = 0
frequency = len(dataList[count])
incount = 1
while incount < frequency:
Sum = Sum + int(dataList[count][incount])
incount = incount + 1
average = Sum / (frequency-1)
entry.append(average)
AverageScore.append(entry)
# this appends the name and average score of the student to the larger array
# 'AverageScore'
count= count + 1
# the count is increased so the process is repeated for the next student
AverageSorted = sorted(AverageScore,key=lambda l:l[1], reverse=True)
# http://stackoverflow.com/questions/18563680/sorting-2d-list-python
# this is code i obtained through someone else's post which arranges the array in descending
# order of scores
count2 = 0
while count2 < len(AverageSorted):
print(AverageSorted[count2][0], ':', AverageSorted[count2][1])
count2 = count2 + 1
# this formats the array so it prints the elements in a list of each student's
# name and score
冗长且效率低下，但它是我能用我对 python 的小知识做的最好的:)
【讨论】：
如果这是1.txt的内容：
John = 1
Joe = 3
John = 7
Joe = 9
Bob = 3
Joe = 8
John = 2
Bob = 9
Roger = 13
用这个替换你的“with”语句：
name = "John"
_class = 1
with open("%s.txt" % _class, "r") as out:
lines = out.readlines()
scores = []
for line in lines:
if name in line:
# "strip" without arguments strips out all beginning
# and trailing white-space (i.e. " ", "\n", "\r").
line = line.strip()
score = int(line.split(" = ")[1])
scores.append(score)
# If there isn't any scores in this list, then there was no user
# data.
if scores:
# Use python built-in sum to sum the list of scores and
# divide the result by the number of scores gives you the average.
average = sum(scores) / len(scores)
print "%s's average score is %.1f out of %d game(s)." % (
name, average, len(scores))
else:
print "User %s not found." % name
【讨论】：
with open("%s.txt" % class, "r") as out:。