遍历数组数组并按顺序显示每个子数组

Question

我有一个包含 3 个不同数组的数组。

$arrayAll = (

    0 => $array1,
    1 => $array2,
    2 => $array3
);

如何遍历 $arrayAll，在每次迭代时显示每个子数组的第一个元素（array1，array2，array3）？

所以，输出将是：

$array1[0],$array2[0],$array3[0],
$array1[1],$array2[1],$array3[1],
$array1[2],$array2[2],$array3[2]

以此类推..直到所有子元素都被获取。

编辑：

$addsContent = $Adds->selectAdds(10);
$sharedArticlesContent = $SharedContent->getSharedContent($topic_selected, $filter_selected);
$blogPostsContent = $BlogPosts->getRecentBlogPostsByTopic("business");

$contentArray = array(

    $sharedArticlesContent,
    $addsContent ,
    $blogPostsContent
);


foreach($contentArray as $value)
    {
        if(count($value)>$maxLength)
        {
            $maxLength = count($value);
        }
    }

for($i=0; $i<$maxLength; $i++)
{
    foreach($contentArray as $value)
    {
        if(isset($value[$i]))
        {
            if($value==$sharedArticlesContent){
                $data = $value[$i];
                foreach($sharedArticlesContent as $data){

                    $post_id = $data['id'];
                    $uploaded_by = $data['uploaded_by'];
                    $text = $data['text'];
                    $image = $data['image'];

                    require 'template1.php';

              }
            }elseif($value==$addsContent){
                //template2
            }else{
               //template3
            }

        }

    }
}

Answer 1

$maxLength = 0;

foreach($arrayAll as $value)
    {
        if(count($value)>$maxLength)
        {
            $maxLength = count($value);
        }
    }

for($i=0; $i<$maxLength; $i++)
{
    foreach($arrayAll as $value)
    {
        if(isset($value[$i]))
        {
            echo $value[$i];    
        }

    }
}