排序json对象数据[重复]答案

【问题标题】：sorting json object data [duplicate]排序json对象数据[重复]
【发布时间】：2014-12-21 15:00:55
【问题描述】：

var json = $.parseJSON(data);
var serializedMyObj = JSON.stringify(json);
console.log(serializedMyObj);

我在控制台中显示了 json 对象，如下所示。现在我想按价格对其进行排序。

[{
    "name": "HTC 816",
    "Manufacture": "htc",
    "price": "45.00",
    "url": "images/products/htc-desire-816-400x400.jpeg",
    "productId": "543J423"
}, {
    "name": "HTC 616",
    "Manufacture": "htc",
    "price": "55.00",
    "url": "images/products/htc-desire-616.jpeg",
    "productId": "543J424"
}, {
    "name": "HTC 716",
    "Manufacture": "htc",
    "price": "32.00",
    "url": "img/list grid.png",
    "productId": "543J425"
}, {
    "name": "HTC 416",
    "Manufacture": "htc",
    "price": "70.00",
    "url": "img/list grid.png",
    "productId": "543J426"
}, {
    "name": "HTC 316",
    "Manufacture": "htc",
    "price": "99.00",
    "url": "",
    "productId": "543J427"
}, {
    "name": "HTC 216",
    "Manufacture": "htc",
    "price": "45.00",
    "url": "",
    "productId": "543J428"
}, {
    "name": "HTC ONE",
    "Manufacture": "htc",
    "price": "25.00",
    "url": "images/products/htc-one-v.jpeg",
    "productId": "543J429"
}, {
    "name": "HTC EYE",
    "Manufacture": "htc",
    "price": "60.00",
    "url": "",
    "productId": "543J430"
}, {
    "name": "HTC DESIRE",
    "Manufacture": "htc",
    "price": "102.00",
    "url": "",
    "productId": "543J431"
}]

【问题讨论】：

标签： javascript jquery json html

【解决方案1】：

使用Array.sort:

var arr = [{
    "name": "HTC 816",
    "Manufacture": "htc",
    "price": "45.00",
    "url": "images/products/htc-desire-816-400x400.jpeg",
    "productId": "543J423"
}, {
    "name": "HTC 616",
    "Manufacture": "htc",
    "price": "55.00",
    "url": "images/products/htc-desire-616.jpeg",
    "productId": "543J424"
}, {
    "name": "HTC 716",
    "Manufacture": "htc",
    "price": "32.00",
    "url": "img/list grid.png",
    "productId": "543J425"
}, {
    "name": "HTC 416",
    "Manufacture": "htc",
    "price": "70.00",
    "url": "img/list grid.png",
    "productId": "543J426"
}, {
    "name": "HTC 316",
    "Manufacture": "htc",
    "price": "99.00",
    "url": "",
    "productId": "543J427"
}, {
    "name": "HTC 216",
    "Manufacture": "htc",
    "price": "45.00",
    "url": "",
    "productId": "543J428"
}, {
    "name": "HTC ONE",
    "Manufacture": "htc",
    "price": "25.00",
    "url": "images/products/htc-one-v.jpeg",
    "productId": "543J429"
}, {
    "name": "HTC EYE",
    "Manufacture": "htc",
    "price": "60.00",
    "url": "",
    "productId": "543J430"
}, {
    "name": "HTC DESIRE",
    "Manufacture": "htc",
    "price": "102.00",
    "url": "",
    "productId": "543J431"
}];

arr.sort(function(a,b){return a.price - b.price});
console.log(arr);

JSFIDDLE

【讨论】：

【解决方案2】：

json.sort(function(a, b) { return a.price - b.price; });//sort ascending

【讨论】：

@RGraham 确实有效。它接受任何正数和负数，因此可以进行简单的减法。阅读您自己的链接中的文章。