【发布时间】:2021-05-29 17:16:25
【问题描述】:
我做了一个石头剪刀布游戏。 它工作正常,正如我想要的那样,但是在第二次运行时它不会存储输入的值,我该如何解决这个问题。
如果用户输入y,请参见下面的while循环。
import random
tools =["Rock","Scissors","Paper"]
r = "".join(tools[0])
s = "".join(tools[1])
p = "".join(tools[-1])
def computer_predicion():
computer_pred = random.choice(tools)
return computer_pred
computer = computer_predicion()
def my_predicion():
my_predicion = input("Choose (R)Rock,(S)Scissors,(P)Paper:")
if my_predicion == "R" or my_predicion == "r":
my_predicion = r
return my_predicion
elif my_predicion == "S" or my_predicion == "s":
my_predicion = s
return my_predicion
elif my_predicion == "P" or my_predicion == "p":
my_predicion = p
return my_predicion
else:
print("Debils ir?")
human=my_predicion()
def game():
message_win = ("You won!")
message_lose = ("You lost!")
message = "Computer:%s\nUser:%s"%(computer, human)
if computer == r and human == r :
print(message+"\nIt's draw")
elif computer == p and human == p:
print(message + "\nIt's draw")
elif computer == s and human == s:
print(message + "\nIt's draw")
elif computer == r and human == p:
print(message+'\n'+message_win)
elif computer == p and human == r:
print(message+'\n'+message_lose)
elif computer == r and human == s:
print(message+'\n'+message_lose)
elif computer == s and human == r:
print(message+'\n'+message_win)
elif computer == p and human == s:
print(message+'\n'+message_win)
elif computer == s and human == p:
print(message+'\n'+message_lose)
else:
pass
c = True
while c: //Here code runs second time if user inputs Y or y.
game()
h = input("Continue?(Y/N):")
if h == "Y" or h == "y":
my_predicion()
computer_predicion()
pass
elif h == "N" or h == "n":
c = False
else:
print("Wrong symbol!")
【问题讨论】:
标签: python list function if-statement random