遍历 Python 中的对象列表

Question

     class Book:
     """Represents information about books.

     attributes: name, author, price, sold_units
     """
         def __init__(self):
             self.name : str = ""
             self.author : str = ""
             self.price : float = 0.0
             self.sold_units : int= 0
        
    def best_book(books : List[Book]) -> str:
    """Returns the name of the book that has sold more units.
    """
       result = ""
       ......
       return result

       titles = ['Think and Grow Rich', 'The Da Vinci Code', 'The Lion, the Witch and the Wardrobe']
    authors = ['Napoleon Hill', 'Dan Brown', 'C.S. Lewis']
    prices = [5, 5, 5]
    sold_units_per_book = [10, 20, 30]

    books = []

    for i in range(10):
        book = Book()
        book.name = titles[i]
        book.author = authors[i]
        book.price = prices[i]
        book.sold_units = sold_units_per_book[i]
        books.append(book)

    best_book(books)

我有对象列表 - 书籍，我需要在我的函数 best_book 中返回已售出更多单位的书籍的名称。

我不知道如何使用 foo 循环遍历对象列表，找到最大值并同时返回书名。 也许是这样的：

    for obj in books:
        max(obj.price)
     

也许有人知道怎么做？

Answer 1

更新（如果最好的书是最赚钱的书）：

def best_book(books : List[Book]) -> str:
   return max(books, key=lambda b: b.price * b.sold_units).name