While 循环，if-else 语句：猜我的数字游戏答案

【问题标题】：While loops, if-else statements: Guess my number gameWhile 循环，if-else 语句：猜我的数字游戏
【发布时间】：2017-04-01 13:53:36
【问题描述】：

我是一个使用 python 的初学者，正在编写一个“猜我的数字游戏”。到目前为止，我一切正常。计算机在 1 到 3 之间选择一个随机数，并要求玩家猜测该数字。如果猜测值高于随机数，则程序打印“Lower”，反之亦然。玩家只有5次尝试，当他们用完时，玩家会收到一条消息，游戏结束。如果玩家猜对了，则恭喜他们，游戏结束。但是，有时当数字猜对时，程序不会打印祝贺信息，我不知道为什么......

import random

print("\tWelcome to 'Guess My Number'!:")
print("\nI'm thinking of a numer between 1 and 100.")
print("Guess carefully, you only have 5 tries!.\n")

#sets initial values
the_number = random.randint(1,3)
guess = int(input("Take a guess: "))
tries = 1
guesses = 4


#guessing loop
while guess != the_number:
    if guess > the_number:
        print("Lower...")
    elif guesses <= 0:
        print("Sorry, you're out of guesses! Try again...")
        break

    elif guess < the_number:
        print("Higher...")



    guess = int(input("Take a guess: "))
    tries += 1
    guesses -= 1

    if guess == the_number:
        print("You guessed it! The number was", the_number)
        print("And it only took you", tries, "tries!\n")

【问题讨论】：

if guess == the_number 在 while 循环内...永远不会是真的
啊……当然。谢谢！

标签： python if-statement while-loop

【解决方案1】：

要回答您关于缺少正确数字的祝贺消息的原始问题，请使用 input() 结束代码，以确保它不会在显示最后一条消息之前终止。

计算顺序：

给出输入猜测
减少猜测（从 5 开始），增加尝试次数（从 1 开始）
如果猜测 == 0 则立即休息
评估猜测（较低、较高或相等，这将结束 while 循环）

import random

print("\tWelcome to 'Guess My Number'!:")
print("\nI'm thinking of a numer between 1 and 3.")
print("Guess carefully, you only have 5 tries!.\n")

#sets initial values
the_number = random.randint(1,3)
guess = int(input("Take a guess: "))
tries = 1
guesses = 5


#guessing loop


while guess != the_number:
    tries += 1
    guesses -= 1

    if guesses == 0:
        print("Sorry, you're out of guesses! Try again...")
        break

    elif guess > the_number:
        print("Lower...")
    elif guess < the_number:
        print("Higher...")

    

    guess = int(input("Take a guess: "))

if guess == the_number:
    print("You guessed it! The number was", the_number)
    print("And it only took you", tries, "tries!\n")

input()

【讨论】：

【解决方案2】：

假设其他一切正常，取消缩进最后的检查。 guess == the_number 不相等时，您无法检查它

#guessing loop
while guess != the_number:
    # do logic

# outside guessing loop
if guesses > 0:
    print("You guessed it! The number was", the_number)
    print("And it only took you", tries, "tries!\n")

【讨论】：

if 仍然需要，因为循环可能会因猜测不足而结束。

【解决方案3】：

如果您在第一次尝试中猜到了数字，那么程序将需要再次猜测，因为

guess = int(input("Take a guess: "))
tries += 1
guesses -= 1

来之前

if guess == the_number:
    print("You guessed it! The number was", the_number)
    print("And it only took you", tries, "tries!\n")

当您已经要求在循环之外进行猜测时。您应该只在循环内要求输入：

the_number = random.randint(1,3)
tries = 0
guesses = 5

#guessing loop
guess = None
while guess != the_number:
    guess = int(input("Take a guess: "))
    tries += 1
    guesses -= 1

    if guess > the_number:
        print("Lower...")
    elif guess < the_number:
        print("Higher...")

    if guess == the_number:
        print("You guessed it! The number was", the_number)
        print("And it only took you", tries, "tries!\n")

    if guesses <= 0:
        print("Sorry, you're out of guesses! Try again...")
        break

【讨论】：