【发布时间】:2019-08-17 04:04:27
【问题描述】:
我正在尝试在 C 程序中模拟 unix shell,但它仍处于开始阶段,最多可用于两个管道。我有一个命令向量 (char *com[3][3]),考虑到字符“|”,它们是分开的,但我的问题是如何在 for 循环中继续处理更多管道?在遵循当前的实现中,我正在尝试执行由管道分隔的 3 个命令:
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <sys/types.h>
int main(int argc, char **argv){
//Vector with positions of pipes found, position 0 reserved for the total amount of commands.
char* com[3][3] = { { "/bin/ls", "-la", 0 },
{ "/bin/grep", ".", 0}, { "/usr/bin/wc", "-l", 0 }};
//EXECUTE COMMANDS
pid_t fork1, fork2, fork3;
int fd1[2], fd2[2];
if(pipe(fd1) < 0){
perror("pipe1");
}
if(pipe(fd2) < 0){
perror("pipe2");
}
//COMMAND 1
fork1 = fork();
if(fork1 == 0){
dup2(fd1[1], STDOUT_FILENO);
close(fd1[0]);
close(fd2[0]);
close(fd2[1]);
execvp(com[0][0], com[0]);
perror("execvp 1");
exit(EXIT_FAILURE);
}
//COMMAND 2
fork2 = fork();
if(fork2 == 0){
dup2(fd1[0], STDIN_FILENO);
dup2(fd2[1], STDOUT_FILENO);
close(fd1[1]);
close(fd2[0]);
execvp(com[1][0], com[1]);
perror("execvp 2");
exit(EXIT_FAILURE);
}
//COMMAND 3
fork3 = fork();
if(fork3 == 0){
dup2(fd2[0], STDIN_FILENO);
close(fd2[1]);
close(fd1[0]);
close(fd1[1]);
execvp(com[2][0], com[2]);
perror("execvp 3");
exit(EXIT_FAILURE);
}
close(fd1[0]);
close(fd1[1]);
close(fd2[0]);
close(fd2[1]);
waitpid(-1, NULL, 0);
waitpid(-1, NULL, 0);
waitpid(-1, NULL, 0);
return 0;
}
如何在 for 循环中生成 com[n][3]?
【问题讨论】:
标签: c unix operating-system pipe