如何从带有路径的列表中创建文件夹树答案

【问题标题】：How to create folder tree from list with paths如何从带有路径的列表中创建文件夹树
【发布时间】：2019-09-07 08:08:21
【问题描述】：

我正在尝试将需要创建的文件夹结构的每个路径放入一个列表中，然后使用os.makedirs() 创建所有这些路径，但出现了问题。仅创建头文件夹，而不创建子文件夹。

def output_folders(trcpaths):
    #trcpath is a list with several paths, example: ['/home/usr/folder1', '/home/usr/folder2']
    global outputfolders
    outputfolders = []
    #Create Paths
    for x, j in enumerate(trcpaths):
        for i in os.listdir(trcpaths[x]):
            if i.endswith('trc'):
                folderpath1 = (j + '/' + i).split('.')[0] #/home/usr/folder1/outputfolder
                folderpath2 = folderpath1 + '/Steps' #/home/usr/folder1/outputfolder/Steps
                folderpath3 = folderpath2 + '/Step_1' #/home/usr/folder1/outputfolder/Steps/Step_1
                folderpath4 = folderpath2 + '/Step_2'
                folderpath5 = folderpath2 + '/Step_3'
                folderpath6 = folderpath2 + '/Step_4'
                folderpath7 = folderpath2 + '/Threshold'

                outputfolders.append(folderpath1)
                outputfolders.append(folderpath2)
                outputfolders.append(folderpath3)
                outputfolders.append(folderpath4)
                outputfolders.append(folderpath5)
                outputfolders.append(folderpath6)
                outputfolders.append(folderpath7)

    #Create Folders
    for j, i in enumerate(outputfolders):
        print(i)
        if os.path.exists(i):
            if j == 0:
                input('The Output-Folder already exists! Overwrite?' )
            shutil.rmtree(i)
            os.makedirs(i)

虽然当我 print(i) 打印正确的文件夹路径时，但只有“头文件夹路径”像 /home/usr/folder1/outputfolder 一样创建，而不是所有后续文件夹路径。为什么会这样？

这是我得到的：

/home/usr/folder1/outputfolder
/home/usr/folder2/outputfolder

但这正是我需要的：

/home/usr/folder1/outputfolder
/home/usr/folder1/outputfolder/Steps
/home/usr/folder1/outputfolder/Steps/Step_1
/home/usr/folder1/outputfolder/Steps/Step_2
/home/usr/folder1/outputfolder/Steps/Step_3
/home/usr/folder1/outputfolder/Steps/Step_4
/home/usr/folder1/outputfolder/Steps/Threshold
/home/usr/folder2/outputfolder
/home/usr/folder2/outputfolder/Steps
/home/usr/folder2/outputfolder/Steps/Step_1
/home/usr/folder2/outputfolder/Steps/Step_2
/home/usr/folder2/outputfolder/Steps/Step_3
/home/usr/folder2/outputfolder/Steps/Step_4
/home/usr/folder2/outputfolder/Steps/Threshold

【问题讨论】：

您使用的确切 python 版本是什么？我在问，因为 os.makedirs() 行为完全依赖于版本。见docs.python.org/3/library/os.html#os.makedirs
Python 3.6.7，我在帖子里编辑过
什么是trcfilename - 它是一个文件夹吗？
是的。它是一个与文件同名的文件夹。我正在分析 trc 文件并希望输出文件夹与输入文件具有相同的名称。对困惑感到抱歉。我把它改成了/outputfolder

标签： python-3.x operating-system

【解决方案1】：

使用此代码保留您的逻辑和编码：

for j, i in enumerate(outputfolders):
    print(i)
    if os.path.exists(i):
        if j == 0:
            input('The Output-Folder already exists! Overwrite?' )
        shutil.rmtree(i)
        os.makedirs(i)

你不创建文件夹..你只删除现有文件夹并在它已经存在时重新创建

我会添加else来完成操作：

for j, i in enumerate(outputfolders):
    print(i)
    if os.path.exists(i):
        if j == 0:
            input('The Output-Folder already exists! Overwrite?' )
        shutil.rmtree(i)
        os.makedirs(i)
    else:
        os.makedirs(i)

【讨论】：

【解决方案2】：

试试这个（在我的 Windows 机器上测试过，但应该也可以在 Linux 上运行）

import os

NUM_OF_STEPS = 5


def make_output_folders(trc_paths):
    output_folders = []
    for idx, path in enumerate(trc_paths):
        for leaf in os.listdir(path):
            if leaf.endswith('trc') and os.path.isdir(os.path.join(path, leaf)):
                trc_folder = os.path.join(path, leaf)
                output_folders.append(os.path.join(trc_folder, 'output_folder', 'Steps'))
                steps_folder = output_folders[-1]
                for x in range(1, NUM_OF_STEPS):
                    output_folders.append(os.path.join(steps_folder, 'Step_{}'.format(x)))
                output_folders.append(os.path.join(trc_folder,'output_folder', 'Threshold'))

        for _path in output_folders:
            print(_path)
            if not os.path.exists(_path):
                os.makedirs(_path)
        output_folders = []


# 'folder_1' contains a sub folder named '1_trc' 
# 'folder_2' contains a sub folder named '2_trc'
make_output_folders(['c:\\temp\\55721430\\folder1', 'c:\\temp\\55721430\\folder2'])

【讨论】：