如何通过主文件夹从许多子文件夹中获取文件？答案

【问题标题】：How could I grab file from many sub-folder via main folder?如何通过主文件夹从许多子文件夹中获取文件？
【发布时间】：2015-06-04 19:30:16
【问题描述】：

如果我有一个主文件夹和许多子文件夹，而我的目标文件位于这些子文件夹中。如何正确设置路径，然后程序可以直接通过我的主文件夹获取这些目标文件？

例如，

Main_folder
>sub_1
>>sub_1_v1
>>>targeted_file.txt  # file I need
>>sub_2_v2
>>>targeted_file.txt  # file I need
>sub_2
>>sub_1_v1
>>>targeted_file.txt  # file I need
>>sub_2_v2
>>>targeted_file.txt  # file I need

这是由 Julien Spronck (Grabbing data from certain files) 创建的程序

def get_all_files(path):
    ## get a generator with all file names
    import os
    import glob
    return glob.iglob(os.path.join(path,'*.txt'))

def get_all_data(files):
    ## get a generator with all the data from all the files
    for fil in files:
        with open(fil, 'r') as the_file:
            for line in the_file:
                yield line

def write_lines_to_file(lines, outfile):
    with open(outfile, 'w') as the_file:
        for line in lines:

            the_file.write(line+'\n')

path = 'blah blah' # path should be given here!
outfile = 'blah.csv'
files = get_all_files(path)
lines = get_all_data(files)
write_lines_to_file(lines, outfile)

我的问题是，我怎样才能正确地给出路径（从主文件夹），然后我可以一次抓取所有目标文件？

谢谢。

【问题讨论】：

标签： python python-2.7 directory

【解决方案1】：

要遍历文件夹，然后是文件，请使用：

import os                                                                                                             

def list_files(dir):                                                                                                  
    r = []                                                                                                            
    subdirs = [x[0] for x in os.walk(dir)]                                                                            
    for subdir in subdirs:                                                                                            
        files = os.walk(subdir).next()[2]                                                                             
        if (len(files) > 0):                                                                                          
            for file in files:                                                                                        
                r.append(subdir + "/" + file)                                                                         
    return r

如下所示：

Python: Iterate through folders, then subfolders and print filenames with path to text file

【讨论】：