即使发生连接错误，Python 也会继续循环遍历列表

Question

我的脚本中有以下结构：

id_list = [1, 2, 3]
for id in id_list:
    data = get_data(id)
    meta = get_metadata(id)
    # If there is a response, continue:
    if((data.json()) and (data.json())['job_status']=='SUCCESS'):
        # Do stuff
    else:
        print('Id is not found')

这里是get_data() 脚本：

def get_data(form_id):
    survey_found = False
    try:
        print("------- Getting data from Source. Please wait. -------\n")
        print("------- Getting data from Source. Please wait. -------\n", file=logfile)
        response.raise_for_status()
        print(response.content)
        survey_found = True
        return response
    except (RuntimeError, TypeError, NameError, snowCtx.connection.errors.Error, requests.exceptions.HTTPError) as e:
        print("******* Error from Source (GETTING DATA): *******\n"+ str(e)+" on form id: "+str(form_id))
        print("******* Error from Source (GETTING DATA): *******\n"+ str(e)+ str(e)+" on form id: "+str(form_id), file=logfile)
        survey_found = False
        return survey_found

我不关心get_meta()，因为条件是get_data()

问题是如果第一个id 不可用，代码将停止执​​行，因为except 部分将引发http 错误。

我需要脚本继续处理列表中的其他 ID。

Answer 1

id_list = [1, 2, 3]
for id in id_list:
    data = get_data(id)
    if isinstance(data, bool) and not data:
        print(f"skipping {id}...")
        continue
    meta = get_metadata(id)
    if((data.json()) and (data.json())['job_status']=='SUCCESS'):
        # Do stuff
    else:
        print('Id is not found')