将命令作为子进程中的第一个命令运行

Question

我有一个可以打开终端的函数：

def open_next_terminal():
    import subprocess

    def rand(path="/tmp"):
        acc = string.ascii_letters
        retval = []
        for _ in range(7):
            retval.append(random.choice(acc))
        return "{}/{}.sh".format(path, ''.join(retval))

    file_path = rand()
    with open(file_path, "a+") as data:
        data.write(
'''
#!/bin/bash
"$@"
exec $SHELL
'''
        )
    subprocess.call(["sudo", "bash", "{}".format(file_path)])
    return file_path

我想在这个新打开的终端中执行任何操作之前运行一个命令。例如：

subprocess.call(["sudo", "bash", "{}".format(file_path)]) #<= is called
ls #<= is run
 #<= some output of files and folders
root@host:~#  #<= the shell is now available

子进程是否允许我在 shell 初始化期间运行“第一个命令”？

Answer 1

只需将shell=True 参数传递给subprocess.call，您就可以将多个命令（以分号或换行符分隔）作为单个字符串运行。

subprocess.call('your_first_command.sh; your_real_work.sh', shell=True)