在python中循环两个文本文件

Question

这是我第一次来这里，我希望能得到您的帮助。 我是 python 新手，我需要你的帮助

我有两个 .txt 文件 这里是一个例子 文件1.txt

customer1.com
customer2.com
customer3.com
customer4.com
customer5.com
customer6.com
customer7.com
customer8.com
customer9.com

file2.txt

service1
service2
service3

我想在 file1.txt 上循环 file2.txt => 像下面的例子

customer1.com/service1
customer1.com/service2  
customer1.com/service3

customer2.com/service1
customer2.com/service2  
customer2.com/service3

customer3.com/service1
customer3.com/service2  
customer3.com/service3

直到 file1.txt 完成。

我还需要做 IF 语句 例如，假设客户编号 3 的服务编号为 2（我的意思是找到文件）

customer3.com/service2 [找到服务]

我需要 customer3 的循环来停止寻找服务并将输出 (customer3.com/service2) 保存在一个名为 file3.txt 的新文件中 并且循环与其他客户一起继续，每个客户都找到了服务，输出保存在 file3.txt 中

我希望你明白我的意思。 谢谢。

Answer 1

试试这个逐行阅读并使用相应的。

file1 = open('file1.txt', 'r')
file2 = open('file2.txt', 'r')
lines1 = file1.readlines()
lines2 = file2.readlines()
for line_from_1 in lines1:
    for line_from_2 in lines2:
        print(line_from_1 + '/' + line_from_2)

Answer 2

您可以使用itertools.product 从每个文件中获取行的笛卡尔积，以获取每个 URL 组合：

from itertools import product

with open("file1.txt") as f1, open("file2.txt") as f2, open(
    "file3.txt", mode="w"
) as out:
    for x, y in product(f1, f2):
        out.write("%s/%s\n" % (x.strip(), y.strip()))

file3.txt

customer1.com/service1
customer1.com/service2
customer1.com/service3
customer2.com/service1
customer2.com/service2
customer2.com/service3
customer3.com/service1
customer3.com/service2
...

Answer 3

循环任务很简单。您需要读取每个文件并将数据保存为列表。然后用该循环顺序编写一个文件。见例子。但我不明白那条黑线和 service found 逻辑。是一般。更具体。

例子：

list1, list2 = [], []

with open("file1.txt", "r") as f1:
    line = f1.readline()
    while line:
        line = line.strip()
        list1.append(line)
        line = f1.readline()
with open("file2.txt", "r") as f2:
    line = f2.readline()
    while line:
        line = line.strip()
        list2.append(line)
        line = f2.readline()
with open("file3.txt", "w") as f3:
    for i in list1:
        for j in list2:
            f3.write(f"{i}/{j}\n")
        f3.write("\n") # just for that black line