【发布时间】:2014-05-20 12:55:27
【问题描述】:
我有一个项目,我将大量数据以文本文件的形式上传到 SQLServer。有一个 python 脚本使用函数SQLUpload 迭代调用 BCP 命令。这个函数的输入是:
SQLUpload(prefix,suffix,uploadingDirectory,formatFileDirectory,server,tableName,
userName,passWord)
使用子流程模块迭代调用BCP命令的行如下(如果需要更多代码,请注释):
batchCommand = 'BCP ' + tableName + ' in ' + os.path.join(directory,dataFile) + ' -U ' \
+ userName + ' -P ' + passWord + ' -S ' + server \
+ ' -f ' + formatFileDirectory
err = subprocess.call(batchCommand,stderr=subprocess.PIPE,shell=True)
错误如下:
Traceback (most recent call last):
File "<pyshell#14>", line 1, in <module>
SQLUpload(prefix,suffix,uploadingDirectory,formatFileDirectory,server,tableName,userName,passWord)
File "H:\Engineering\MWDownload\HDC\Scriptfile\SQLUploader - Local.py", line 66, in SQLUpload
err = subprocess.call(batchCommand,stderr=subprocess.PIPE,shell=True)
File "C:\Python33\lib\subprocess.py", line 523, in call
with Popen(*popenargs, **kwargs) as p:
File "C:\Python33\lib\subprocess.py", line 789, in __init__
errread, errwrite) = self._get_handles(stdin, stdout, stderr)
File "C:\Python33\lib\subprocess.py", line 1006, in _get_handles
c2pwrite = self._make_inheritable(c2pwrite)
File "C:\Python33\lib\subprocess.py", line 1038, in _make_inheritable
_winapi.DUPLICATE_SAME_ACCESS)
OSError: [WinError 6] The handle is invalid
此错误是否意味着我没有使用当前用户名和密码的权限?还是有别的意思?
提前致谢。
【问题讨论】:
-
由于某种原因重新启动工作。我再次运行脚本。它从它离开的地方拿起然后工作。奇怪。以下是有关 Windows 句柄的一些信息:stackoverflow.com/questions/902967/what-is-a-windows-handle
标签: python sql-server command-line subprocess bcp