如何解析来自 Unirest 调用的 JSON 结果答案

【问题标题】：How to parse JSON results from Unirest call如何解析来自 Unirest 调用的 JSON 结果
【发布时间】：2014-07-01 02:14:41
【问题描述】：

我正在使用Unirest library 从 Mashape API 中检索 JSON。我使用以下代码拨打电话：

HttpResponse<JsonNode> request = Unirest.get(URL)
  .header("X-Mashape-Authorization", MASHAPE_AUTH)
  .asJson();

这会以我不熟悉的HttpResponse<JsonNode> 的形式返回我的 JSON。

通过阅读有限的documentation，看来我必须在响应对象上调用getBody() 才能取回JsonNode 对象。但是，我仍然不知道如何处理 JsonNode 对象。

开始解析这些数据的最佳方法是什么？

编辑： 如果它有助于提供示例，我要解析的 JSON 如下所示：

{
  "success": "1",
  "error_number": "",
  "error_message": "",
  "results": [
    {
      "name": "name1",
      "formatedName": "Name 1"
    },
    {
      "name": "testtesttest",
      "formatedName": "Test Test Test"
    },
    {
      "name": "nametest2",
      "formatedName": "Name Test 2"
    },
    {
      "name": "nametest3",
      "formatedName": "Name Test 3"
    }
  ]
}

【问题讨论】：

我找不到任何详细说明图书馆这一部分的文档。因此我问这个问题。你用过 Unirest 库吗？你知道有什么好的文档可以帮助我吗？
尝试打印 JsonNode.toString() 并告诉我它将显示什么...
@Haresh，刚刚尝试过，它会打印出我所追求的 Json。就像我在主帖中编辑的 json 一样。
unirest.io/java.html 上的文档似乎表明您在解析 JSON 方面是靠自己的，并建议使用 Jackson。只是我，还是这远不如groovyx.net.http.RESTClient方便，它返回一个response对象，response.data.blah可以检索任意JSON键

标签： java android json unirest mashape

【解决方案1】：

今天试图为自己解决这个问题。源代码可能是您将获得的唯一文档。这是tl;博士

// the request from your question
HttpResponse<JsonNode> request = Unirest.get(URL)
  .header("X-Mashape-Authorization", MASHAPE_AUTH)
  .asJson();

// retrieve the parsed JSONObject from the response
JSONObject myObj = request.getBody().getObject();

// extract fields from the object
String msg = myObj.getString("error_message");
JSONArray results = myObj.getJSONArray();

以下是对我所做的洞穴探险的更多解释：

从the HttpResponse class 我们可以看到getBody() 将返回实例变量body，它在第92 行被赋值为：

this.body = (T) new JsonNode(jsonString)

那么我们需要查看the JsonNode class。构造函数采用表示要解析的 JSON 的字符串并尝试创建 JSONObject 或 JSONArray。谢天谢地，这些对象来自org.json，即well documented。

【讨论】：

【解决方案2】：

由于响应很容易作为字符串检索，因此如果您不想手动遍历 JSON，则可以使用任何您想要的 JSON 库进行反序列化。我个人偏爱 Google 的 GSON，它能够轻松地将您的 JSON 响应映射到您创建的匹配对象。

HttpRequest request = Unirest.get(/*your request URI*/)
                .headers(/*if needed*/)
                .queryString(/*if needed*/);

HttpResponse<JsonNode> jsonResponse = request.asJson();
Gson gson = new Gson();
String responseJSONString = jsonResponse.getBody().toString();
MyResponseObject myObject = gson.fromJson(responseJSONString, String.class);

【讨论】：

这说不通，有asString的时候为什么还要用asJson再用toString？

【解决方案3】：

在 JSON 字符串中，有两个符号可以引导您完成解析：

{ - 表示一个 JSONObject

[ - 表示一个 JSONArray

在解析 json 字符串时，您应该迭代地遍历这些项目。要了解您的 string 中有多少 JsonObjects 和 JsonArrays 以及您应该从哪些开始解析，请使用 json-visualizer 工具，如 this website。例如，您的字符串的结构是这样的：

如您所见，根对象是一个 JSONObject，它由一个带有三个 jsonOnject 的 JSONArray 组成。要解析这样的结构，您可以使用：

JSONObject jsonobj = new JSONObject(jsonstring);

String result = jsonObject.getString("success");
String error_number = jsonObject.getString("error_number");    
String error_message = jsonObject.getString("error_message"); 

JSON Array jsonarray = jsonobj.getJSONArray();

String[] names = new String[jsonArray.length()];    
String[] formattedNames = new String[jsonArray.length()];  

for(int i=0;i<jsonArray.length();i++)
{
    JSONObject jsonObject = jsonArray.getJSONObject(i);

    names [i] = jsonObject.getString("name");
    formattedNames [i] = jsonObject.getString("formattedName");
  }

【讨论】：

【解决方案4】：

Unirest 中有一个序列化功能（可能是在 2015 年和 2014 年的答案之后出现的）。在当前版本 1.4.9 中，您可以使用方便的 asObject(Class) 和 body(Object) 方法。以下是反序列化 AWS CloudSearch 响应的示例。

import java.util.Arrays;

import org.apache.http.HttpStatus;

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
import com.mashape.unirest.http.HttpResponse;
import com.mashape.unirest.http.ObjectMapper;
import com.mashape.unirest.http.Unirest;
import com.mashape.unirest.http.exceptions.UnirestException;

public class UnirestExample {
    public class Item {
        private String full4kurl;
        private String previewurl;
        private String description;

        @Override
        public String toString() {
            return "{full4kurl:" + full4kurl + ", previewurl:" + previewurl
                    + ", description:" + description + "}";
        }
    }

    public class Hit {
        private String id;
        private Item fields;

        @Override
        public String toString() {
            return "{id:" + id + ", fields:" + fields + "}";
        }
    }

    public class Hits {
        private int found;
        private int start;
        private Hit[] hit;

        @Override
        public String toString() {
            return "{found:" + found + ", start:" + start + ", hit:"
                    + Arrays.toString(hit) + "}";
        }
    }

    public class CloudSearchResult {
        private Hits hits;

        @Override
        public String toString() {
            return "{hits:" + hits + "}";
        }
    }

    public static final String END_POINT = "AWS CloudSearch URL";

    static {
        Unirest.setTimeouts(1000, 5000);

        Unirest.setObjectMapper(new ObjectMapper() {
            private Gson gson = new GsonBuilder().disableHtmlEscaping()
                    .create();

            @Override
            public <T> T readValue(String value, Class<T> valueType) {
                return gson.fromJson(value, valueType);
            }

            @Override
            public String writeValue(Object value) {
                return gson.toJson(value);
            }
        });
    }

    public static void main(String[] args) throws UnirestException {
        HttpResponse<CloudSearchResult> response = Unirest.post(END_POINT)
                .header("Header", "header").body("body")
                .asObject(CloudSearchResult.class);
        if (response.getStatus() == HttpStatus.SC_OK) {
            CloudSearchResult body = response.getBody();
            System.out.println(body);
        } else {
            throw new RuntimeException("Fail to invoke URL ");
        }
    }
}

【讨论】：

【解决方案5】：

您可以检索 JsonNode 的主体，然后将 JsonNode 转换为 JSONObject 以访问值。为了访问结果，您可以将其转换为 JSONArray。

import org.json.*;
HttpResponse<JsonNode> request = Unirest.get(URL).header("X-Mashape 
Authorization", MASHAPE_AUTH).asJson();
JSONObject responsejson = request.getBody().getObject();
JSONArray results = responsejson.getJSONArray("results");

然后您可以遍历结果中的每个 JSONObject。例如获取结果中的第一个对象

JSONObject value = results.getJSONObject(0);

【讨论】：

【解决方案6】：

这应该对我有用

System.out.println(request.getBody().getObject().toString(2));

示例代码

import com.mashape.unirest.http.HttpResponse;
import com.mashape.unirest.http.JsonNode;
import com.mashape.unirest.http.Unirest;

public class UnirestClient{
public void getQuestions() throws Exception {
HttpResponse<JsonNode> stack= Unirest.get("https://api.stackexchange.com/2.2/questions").
    header("accept",  "application/json").
    queryString("order","desc").
    queryString("sort", "creation").
    queryString("filter", "default").
    queryString("site", "stackoverflow").
    asJson();
System.out.println(stack.getBody().getObject().toString(2));
 }

public static void main(String args[]) throws Exception {
JavaHTTPAPIClient client = new JavaHTTPAPIClient();
client.getQuestionsUsingUnirest();
 }
}

回应

    {
      "quota_max": 300,
      "items": [
        {
          "creation_date": 1477998742,
          "tags": [
            "javascript",
            "spring",
            "sockjs",
            "spring-js",
            "sockjs-tornado"
          ],
          "title": "Sockjs 404 not found",
          "link": "http://stackoverflow.com/questions/40358911/sockjs-404-not-found",
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          "tags": [
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            "html",
            "email",
            "magento",
            "static-block"
          ],
          "title": "Creating a magento email template: custom static block not working",
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          "title": "Random number Powerpoint as slide change",
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【讨论】：

【解决方案7】：

// try this way,hope this will help you...

        String respone  = "{\n" +
               "  \"success\": \"1\",\n" +
               "  \"error_number\": \"\",\n" +
               "  \"error_message\": \"\",\n" +
               "  \"results\": [\n" +
               "    {\n" +
               "      \"name\": \"name1\",\n" +
               "      \"formatedName\": \"Name 1\"\n" +
               "    },\n" +
               "    {\n" +
               "      \"name\": \"testtesttest\",\n" +
               "      \"formatedName\": \"Test Test Test\"\n" +
               "    },\n" +
               "    {\n" +
               "      \"name\": \"nametest2\",\n" +
               "      \"formatedName\": \"Name Test 2\"\n" +
               "    },\n" +
               "    {\n" +
               "      \"name\": \"nametest3\",\n" +
               "      \"formatedName\": \"Name Test 3\"\n" +
               "    }\n" +
               "  ]\n" +
               "}";

        try{

            JSONObject responeJson = new JSONObject(respone);
            if(responeJson.getString("success").equals("1")){
                JSONArray jsonArray = responeJson.getJSONArray("results");

                for (int i=0;i<jsonArray.length();i++){
                    System.out.println("Name : "+jsonArray.getJSONObject(i).getString("name"));
                    System.out.println("FormatedName : "+jsonArray.getJSONObject(i).getString("formatedName"));
                }
            }else{
                Toast.makeText(this,responeJson.getString("error_message"),Toast.LENGTH_SHORT).show();
            }
        }catch (Throwable e){
            e.printStackTrace();
        }

【讨论】：