从 python 3.3 运行终端命令

Question

我正在尝试从 python 3.3（mac osx 10.7.5）运行 wkhtmltopdf（将 html 转换为 pdf 的例程：http://wkhtmltopdf.org）命令。

当使用以下命令直接在终端上运行时，该例程就像一个魅力：

wkhtmltopdf http:google.com /Users/ME/Desktop/google.pdf

其中 http:google.com 是目标文件中将转换为 pdf 的 html：/Users/ME/Desktop/google.pdf

但是当从 python 调用 shell 时：

import subprocess

subprocess.call(["wkhtmltopdf http:google.com /Users/ME/Desktop/google.pdf"])

我明白了：

> Traceback (most recent call last):   File "<pyshell#5>", line 1, in
<module>
    subprocess.call(["wkhtmltopdf http:google.com /Users/thenoze/Desktop/google.pdf"])   File
"/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/subprocess.py",
line 523, in call
    with Popen(*popenargs, **kwargs) as p:   File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/subprocess.py",
line 824, in __init__
    restore_signals, start_new_session)   File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/subprocess.py",
line 1448, in _execute_child
    raise child_exception_type(errno_num, err_msg) FileNotFoundError: [Errno 2] No such file or directory: 'wkhtmltopdf http:google.com /Users/ME/Desktop/google.pdf'

--> 任何线索如何格式化我的 subprocess.call() ？

Answer 1

将命令行参数分隔为列表项：

subprocess.call(["wkhtmltopdf", "http:google.com", "/Users/ME/Desktop/google.pdf"])

否则，wkhtmltopdf ... google.pdf 将被视为程序路径，而不是 wkhtmltopdf。