如何快速解析字符串

Question

我的json是这样的：

"billerdetails": [
{
"id": "1",
"bname": "ACT Fibernet",
"bcustomerparms": "[{\"paramName\":\"Account Number/User Name\",\"dataType\":\"ALPHANUMERIC\",\"optional\":\"false\",\"minLength\":\"1\",\"maxLength\":\"50\"}]",
"breponseParams": "[{\"amtBreakupList\":[{\"amtBreakup\":\"BASE_BILL_AMOUNT\"}]}]",
......

在这里我可以得到bcustomerparms。但在这里我需要 bcustomerparms：paramName 值，例如（帐号/用户名）在一个 virable 中.. 为此我编写了如下代码，但我无法在 vairable 中获取帐号/用户名。

请在下面的代码中帮助我：

do{
let jsonObj = try JSONSerialization.jsonObject(with: respData, options: .allowFragments) as! [String: Any]
//print("the all make payment json is \(jsonObj)")

let billerdetailsArray = jsonObj["billerdetails"] as! [[String: Any]]

for billerdetail in billerdetailsArray {

    self.categoryName = billerdetail["bname"] as? String
    var customrParams = billerdetail["bcustomerparms"]
    print("biller customrParams \(customrParams)") 
 }

// 这里我得到 bcustomerparms

biller customrParams Optional([{"paramName":"Connection ID","dataType":"ALPHANUMERIC","optional":"false","minLength":"8","maxLength":"10"} ])

但在这里我只想要 paramName 值如何获取该值。请在上面的代码中帮助我。

Answer 1

bcustomerparms值是字符串不是字典数组，你可以试试

let customrParams = billerdetail["bcustomerparms"] as! String
let res = try JSONSerialization.jsonObject(with:Data(customrParams.utf8)) as! [[String: Any]]
for item in res {
  print(item["paramName"])
}