如何从字典中进行摘要交易？答案

【问题标题】：how can i make summary transaction from dictionary?如何从字典中进行摘要交易？
【发布时间】：2020-09-25 09:42:43
【问题描述】：

我有这样的代码：

bought = {'Banana':2, 'Avocado':3, 'Cherries':1}
price_of = {'Apple': 6,
'Avocado': 5,
'Banana': 3,
'Blackberries': 10,
'Blueberries': 12,
'Cherries': 7,
'Pineapple': 7}

bought = sorted(bought) 
def print_summary(items,fprice):
   items = bought
   for item, n in fprice.items():
      print(n, item, ':', n * items[item])
      print('total', sum(n * items[item])

print_summary(bought,price_of)

但我得到这样的输出：

enter image description here

我想让输出是这样的：

3 Avocado : 15
2 Banana : 6
1 Cherries : 7
total : 28

【问题讨论】：

counter_item 和 chart 是什么

标签： python function loops dictionary

【解决方案1】：

这里您想根据键值以相反的顺序对字典进行排序，因此您必须在代码中添加它。这里主要关注的是排序，所以我以简单的方式完成了值的乘法。

bought = {'Banana':2, 'Avocado':3, 'Cherries':1}
price_of = {'Apple': 6,
'Avocado': 5,
'Banana': 3,
'Blackberries': 10,
'Blueberries': 12,
'Cherries': 7,
'Pineapple': 7}

bought['Banana'] *= price_of['Banana']
bought['Avocado'] *= price_of['Avocado']
bought['Cherries'] *= price_of['Cherries']

lst = list()
for k,v in bought.items():
    newtup = (v,k)
    lst.append(newtup)

lst = sorted(lst, reverse = True)
n=3
total = 0
for k,v in lst:
    print(n,' ',v,' : ',k)
    total = total + k
    n = n-1
print('total :', total)

这段代码的输出是：

3   Avocado  :  15
2   Cherries  :  7
1   Banana  :  6
total : 28

【讨论】：

【解决方案2】：

我弄得有点乱，但可以工作

bought = {'Banana':2, 'Avocado':3, 'Cherries':1}
price_of = {'Apple': 6,
'Avocado': 5,
'Banana': 3,
'Blackberries': 10,
'Blueberries': 12,
'Cherries': 7,
'Pineapple': 7}

#Creating a new sorted dictionary named b
a = sorted(bought)
b = {}
for fruit in a:
    b[fruit] = bought.get(fruit)
#Making bought be b
bought = b

def summary(items, price):
    total = 0
    for i in items:
        print(f" {items.get(i)} {i} : {items.get(i)*price.get(i)}")
        total = total + items.get(i)*price.get(i)
    print(f" Total {total}")

summary(bought, price_of)

希望对你有帮助

【讨论】：

【解决方案3】：

bought = {'Banana':2, 'Avocado':3, 'Cherries':1}
price_of = {'Apple': 6,
'Avocado': 5,
'Banana': 3,
'Blackberries': 10,
'Blueberries': 12,
'Cherries': 7,
'Pineapple': 7}

# bought = sorted(bought)
def print_summary(items,fprice):
#    items = counter_item(chart)
#    for item, n in fprice.items():
#       print(n, item, ':', n * items[item])
#       print('total', sum(n * items[item]))
    total = 0
    for i, k in enumerate(sorted(items, key= lambda x: items[x], reverse=True )):
        print(items[k], k, ':', items[k] * fprice[k])
        total += items[k] * fprice[k]
    print("total : {}".format(total))

print_summary (bought,price_of)

3 Avocado : 15
2 Banana : 6
1 Cherries : 7
total : 28

【讨论】：

【解决方案4】：

for fruit, quantity in sorted(bought.items()):
    print(f"{quantity} {fruit} : {quantity * price_of[fruit]}")
print(f"total : {sum(quantity * price_of[fruit] for fruit, quantity in bought.items())}")

【讨论】：