用于比较数组中不同字典的 Javascript 循环

Question

我想将具有教练对象某些偏好的词典与其他包含教练简介的词典进行比较。

所以每个教练都得到了他与教练对象偏好匹配程度的分数，或者因为他不匹配重要的偏好而被排除在 -1 分。

一位教练员将与 24 位教练进行比较，并得到一个分数，这样我就可以看到哪个是最好的匹配。

问题：如何循环播放？

这是一个代码示例：

//coachee\\

var coachee = {

    "geschlecht": 1,

    "alter_option_1": 1,
    "alter_option_2": 1,
    "alter_option_3": 0,

    "themen_option_1": 1,
    "themen_option_2": 0,
    "themen_option_3": 0,

    "branche_option_1": 1,
    "branche_option_2": 0,
    "branche_option_3": 0,

    "erfahrung_option_1": 1,
    "erfahrung_option_2": 0,
    "erfahrung_option_3": 1,

    "sprache_option_1": 1,
    "sprache_option_2": 0,
    "sprache_option_3": 0,
}

//coach1\\

var coach1 = {
    coach1_answers_geschlecht : 2,

    coach1_answers_alter_option_1 : 0,
    coach1_answers_alter_option_2 : 1,
    coach1_answers_alter_option_3 : 0,

    coach1_answers_themen_option_1 : 1,
    coach1_answers_themen_option_2 : 0,
    coach1_answers_themen_option_3 : 1,

    coach1_answers_branche_option1 : 1,
    coach1_answers_branche_option2 : 1,
    coach1_answers_branche_option3 : 0,

    coach1_answers_erfahrung_option1 : 1,
    coach1_answers_erfahrung_option2 : 1,
    coach1_answers_erfahrung_option3 : 0,

    coach1_answers_sprache_option_1 : 1, 
    coach1_answers_sprache_option_2 : 1,
    coach1_answers_sprache_option_3 : 1,
};

///COMPARISON\\\

//Themen\\


if (answers["themen_option_1"] == 1 && coach1_answers_themen_option_1 == 1) {
    coach1_themen1_score = 1;
} else {
    coach1_themen1_score = 0
}
if (answers["themen_option_2"] == 1 && coach1_answers_themen_option_2 == 1) {
    coach1_themen2_score = 1;
} else {
    coach1_themen2_score = 0
}
if (answers["themen_option_3"] == 1 && coach1_answers_themen_option_3 == 1) {
    coach1_themen3_score = 1;
} else {
    coach1_themen3_score = 0
}

var coach1_themen_score = coach1_themen1_score + coach1_themen2_score + coach1_themen3_score 

//Branche\\

if (answers["branche_option_1"] == 1 && coach1_answers_branche_option1 == 1) {
    coach1_branche1_score = 1;
} else {
    coach1_branche1_score = 0
}
if (answers["branche_option_2"] == 1 && coach1_answers_branche_option2 == 1) {
    coach1_branche2_score = 1;
} else {
    coach1_branche2_score = 0
}
if (answers["branche_option_3"] == 1 && coach1_answers_branche_option3 == 1) {
    coach1_branche3_score = 1;
} else {
    coach1_branche3_score = 0
}

var coach1_branche_score = coach1_branche1_score + coach1_branche2_score + coach1_branche3_score

//Erfahrung\\

if (answers["erfahrung_option_1"] == 1 && coach1_answers_erfahrung_option1 == 1) {
    coach1_erfahrung1_score = 1;
} else {
    coach1_erfahrung1_score = 0
}
if (answers["erfahrung_option_2"] == 1 && coach1_answers_erfahrung_option2 == 1) {
    coach1_erfahrung2_score = 1;
} else {
    coach1_erfahrung2_score = 0
}if (answers["erfahrung_option_3"] == 1 && coach1_answers_erfahrung_option3 == 1) {
    coach1_erfahrung3_score = 1;
} else {
    coach1_erfahrung3_score = 0
}

var coach1_erfahrung_score = coach1_erfahrung1_score + coach1_erfahrung2_score + coach1_erfahrung3_score

//Score\\

var coach1_score = (coach1_alter_score + coach1_themen_score + coach1_branche_score + coach1_erfahrung_score)*10

///EXCLUSION\\\

//Alter\\

if (answers["alter_option_1"] == 1 && coach1_answers_alter_option_1 == 1) {
    coach1_alter_score = 1;
} else if (answers["alter_option_2"] == 1 && coach1_answers_alter_option_2 == 1) {
    coach1_alter_score = 1;
} else if (answers["alter_option_3"] == 1 && coach1_answers_alter_option_3 == 1) {
    coach1_alter_score = 1;
} else {
    coach1_score = -1
}

//Sprache\\

if (answers["sprache_option_1"] == 1 && coach1_answers_sprache_option_1 == 1 ) {
  coach1_sprache_score = 1;
} else if (answers["sprache_option_2"] == 1 && coach1_answers_sprache_option_2 == 1 ) {
    coach1_sprache_score = 1;
} else if (answers["sprache_option_3"] == 1 ) {
  coach1_sprache_score = 1;
} else {
  coach1_score = -1;
}

//Geschlecht\\

if (answers["geschlecht"] == 3) {
    coach1_geschlecht_score = 1;
} else if (answers["geschlecht"] == coach1_answers_geschlecht) {
    coach1_geschlecht_score = 1;
} else {
    coach1_score = -1;
}

//Coach2\\


var coach2 = {
    coach2_answers_geschlecht : 2,

    coach2_answers_alter_option_1 : 0,
    coach2_answers_alter_option_2 : 1,
    coach2_answers_alter_option_3 : 0,

    coach2_answers_themen_option_1 : 1,
    coach2_answers_themen_option_2 : 1,
    coach2_answers_themen_option_3 : 1,

    coach2_answers_branche_option1 : 1,
    coach2_answers_branche_option2 : 1,
    coach2_answers_branche_option3 : 0,

    coach2_answers_erfahrung_option1 : 1,
    coach2_answers_erfahrung_option2 : 1,
    coach2_answers_erfahrung_option3 : 0,

    coach2_answers_sprache_option_1 : 1, 
    coach2_answers_sprache_option_2 : 1,
    coach2_answers_sprache_option_3 : 1,
};

因此，我想要一个包含所有分数的数组，例如：

coaches_score = [coach1_score, coach2_score, ...]

我会手动为每个教练重复 //COMPARISON\ 和 //EXCLUSION\ 块，但我必须这样做 24 次。有没有办法循环这个？

非常感谢各位。

Answer 1

好的，我仍然没有得到代码，因为这对于我对 Java Script 的理解来说是一种复杂的方式，但我仍然让它为我工作。我将其编辑为代码：

var coach1_values = getScore(coach1)

var coach2_values = getScore(coach2)

var coach3_values = getScore(coach3);

//Summieren der Werte zum Score\\

const sumValues = obj => Object.values(obj).reduce((a, b) => a + b);

if (coach1_values.score != -1) {
    var coach1_score = sumValues(coach1_values);
} else coach1_score = -1;

if (coach2_values.score != -1) {
    var coach2_score = sumValues(coach2_values);
} else coach2_score = -1;

if (coach3_values.score != -1) {
    var coach3_score = sumValues(coach3_values);
} else coach3_score = -1;

如果它与“geschlecht”匹配，我不明白为什么分数会得到 110，但这没问题，因为每个人的分数都是 110。再次感谢

Answer 2

我建议将数据结构更改为具有数组的更可迭代的样式，并使用相同的键来计算一组键的分数。

const
    getScore = coach => {
        const
            score = {},
            keys1 = ['themen', 'branche', 'erfahrung'],
            keys2 = ['alter', 'sprache'];

        keys1.forEach(k => score[k] = coachee[k].reduce((s, v, i) => s + v * coach[k][i], 0));

        score.score = keys1.reduce((s, k) => s + score[k], 0) * 10;

        keys2.forEach(k => {
            score[k] = +coachee[k].slice(0, -1).some((v, i) => v * coach[k][i]) || +coach1[k][coach[k].length - 1] || 0;
            if (!score[k]) score.score = -1;
        });

        score.geschlecht = +(coach.geschlecht === 3 || coachee.geschlecht === coach.geschlecht)
        if (!score.geschlecht) score.score = -1;

        return score;
    },
    coachee = {
        geschlecht: 1,
        alter: [1, 1, 0, 0],
        themen: [1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1],
        branche: [1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0],
        erfahrung: [1, 0, 1, 0, 0],
        sprache: [1, 0, 0]
    },
    coach1 = {
        geschlecht: 2,
        alter: [0, 1, 0, 1],
        themen: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1],
        branche: [1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 0, 0, 1, 0, 1, 1],
        erfahrung: [1, 1, 0, 0, 1],
        sprache: [1, 1, 1]
    };

console.log(getScore(coach1));