【问题标题】:Reformatting Dictionary output in python在python中重新格式化字典输出
【发布时间】:2015-08-20 20:25:23
【问题描述】:

我有一个 OrderedDict,我已将其导出为 csv,但我希望它采用不同的格式。

我的阅读、排序和制作字典的代码:

from collections import defaultdict, OrderedDict

counts = defaultdict(lambda: {"User": 0, "Equipment": 0, "Neither": 0})
with open('sorterexample.csv', 'rb') as fh: 
    reader = csv.reader(fh, delimiter=',') 
    headerline = reader.next()
    for row in reader: 
        company, calltype = row[0], row[2]
        counts[company][calltype] += 1
        sorted_counts = OrderedDict(sorted(counts.iteritems(), key=lambda   counts_tup: sum(counts_tup[1].values()), reverse=True))

print(sorted_counts)
    writer = csv.writer(open('sortedcounts.csv', 'wb'))
    for key, value in sorted_counts.items():
        writer.writerow([key, value])

我的输出:

OrderedDict([('Customer1', {'Equipment': 0, 'Neither': 1, 'User': 4}), ('Customer3', {'Equipment': 1, 'Neither': 1, 'User': 2}), ('Customer2', {'Equipment': 0, 'Neither': 0, 'User': 1}), ('Customer4', {'Equipment': 1, 'Neither': 0, 'User': 0})])

我的 CSV:

Customer1,  {'Equipment': 0, 'Neither': 1, 'User': 4}
Customer3,  {'Equipment': 1, 'Neither': 1, 'User': 2}
Customer2,  {'Equipment': 0, 'Neither': 0, 'User': 1}
Customer4,  {'Equipment': 1, 'Neither': 0, 'User': 0}

我希望它看起来像这样:

Top Calling Customers,         Equipment,    User,    Neither,
Customer 1,                      0,           4,        1,
Customer 3,                      1,           2,        1,
Customer 2,                      0,           1,        0,
Customer 4,                      1,           0,        0,

我怎样才能格式化它以便它在我的 csv 中以这种方式显示?

编辑:我查看了https://docs.python.org/2.7/howto/sorting.html、itemgetter(),并在 python (How do I sort a list of dictionaries by values of the dictionary in Python?) 中按值排序字典,但我仍然无法让它看起来像我想要的那样。

【问题讨论】:

标签: python csv formatting ordereddictionary


【解决方案1】:

这将按照您描述的方式对其进行格式化:首先它使用列表中的第一个条目写入标题行以找出列的名称,然后写入其余行。

writer = csv.writer(open('sortedcounts.csv', 'wb'))
header = ['Top Calling Customers'] + list(list(sorted_counts.values())[0].keys())
writer.writerow(header)
for key, value in sorted_counts.items():
    writer.writerow([key] + list(value.values()))

【讨论】:

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